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nadya68 [22]
3 years ago
10

An employer wishes to compare typing speeds of graduates from 2 different study programs: A and B. Eight random graduates from c

ourse A type at 62, 85, 59, 64, 73, 70, 75, and 72 words per minute. Six random graduates from course B type at 75, 64, 81, 55, 69, and 58 words per minute. You are to find the 90% confidence interval for the mean difference between the typing speeds of course A and B. In order to do this, you will need to complete a 2 sample t-test for the difference in means.
Mathematics
1 answer:
Karolina [17]3 years ago
8 0

Answer:

Calculated value t =  0.614< 1.782

we accepted null hypothesis for 12 degrees of freedom at 0.05 level of significance .

<u>Step-by-step explanation:</u>

<u>we will t-test </u> t = x⁻- y⁻ /S√ n₁+n₂-2

Given An employer wishes to compare typing speeds of graduates from 2 different study programs: A and B

course A type at 62, 85, 59, 64, 73, 70, 75, and 72

mean of x is x⁻ = ∑x / n

mean of x = 62+85+59+64+73+70+75+ 72 /8 = 70

x⁻ = 70

course B type at 75, 64, 81, 55, 69, and 58

mean of y is  y⁻ = ∑y / n = 75+64+81+55+69+ 58/6 = 67

y⁻ =67

course A    course B

    x                    y             x- x⁻     (x-x⁻ )^2     y- y⁻     (y-y⁻ )^2    

    62                75            8             64          8            64

    85                64           15            225       -3             9

    59                81           -11            121          14            196      

    64                55           -6            36          -12          144          

    73                69          3                9            2            4

    70               58            0              0           -9            81

    75                              5              25

    72                              2               4

                                            ∑( (x-x⁻ )^2= 484           ∑( (y-y⁻ )^2= 498

Adding ∑( (x-x⁻ )^2+ ∑( (y-y⁻ )^2= 982

n₁+n₂-2 = 8+6-2=12

now S^2 =  982/ 12 =81.833

<u>Null hypothesis :H₀:μ₁=μ₂ ( there is no difference between A and B)</u>

<u>Alternative hypothesis :H₁:μ₁≠μ₂</u>

<u>level of significance ∝=0.05</u>

<u>we will use t-test </u> t =   0.614 ( see attachment )

The degrees of freedom = n₁+n₂-2 = 8+6-2=12

From tabulated value  t = 1.782

Calculated value t = 0.614< 1.782

we accepted null hypothesis for 12 degrees of freedom at 0.05 level of significance .

There is no difference between Course A and Course B

Download docx
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Question is Incomplete; Complete question is given below;

Marlene rides her bike at a rate of 16 miles per hour. The time in hours that she rides is represented by the variable t, and the distance she rides is represented by the variable d. Which statements are true of the scenario? Check all that apply.

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