Answer : The new volume of the balloon is, 22.4 L
Explanation :
Charles' Law : It is defined as the volume of gas is directly proportional to the temperature of the gas at constant pressure and number of moles.
![V\propto T](https://tex.z-dn.net/?f=V%5Cpropto%20T)
or,
![\frac{V_1}{V_2}=\frac{T_1}{T_2}](https://tex.z-dn.net/?f=%5Cfrac%7BV_1%7D%7BV_2%7D%3D%5Cfrac%7BT_1%7D%7BT_2%7D)
where,
= initial volume of gas = 22.6 L
= final volume of gas = ?
= initial temperature of gas = ![7^oC=273+7=280K](https://tex.z-dn.net/?f=7%5EoC%3D273%2B7%3D280K)
= final temperature of gas = ![5^oC=273+5=278K](https://tex.z-dn.net/?f=5%5EoC%3D273%2B5%3D278K)
Now put all the given values in the above formula, we get the final volume of the gas.
![\frac{22.6L}{V_2}=\frac{280K}{278K}](https://tex.z-dn.net/?f=%5Cfrac%7B22.6L%7D%7BV_2%7D%3D%5Cfrac%7B280K%7D%7B278K%7D)
![V_2=22.4L](https://tex.z-dn.net/?f=V_2%3D22.4L)
Therefore, the new volume of the balloon is, 22.4 L
Answer:
The answer is C.
Explanation:
because measuring the pH of a substance is a chemical property. The substance must react with the litmus paper to determine its adcidity
<u>Answer:</u> The heat of formation of oleic acid is -94.12 kJ/mol
<u>Explanation:</u>
We are given:
Heat of combustion of oleic acid = ![-1.11\times 10^4kJ/mol](https://tex.z-dn.net/?f=-1.11%5Ctimes%2010%5E4kJ%2Fmol)
The chemical equation for the combustion of oleic acid follows:
![C_{18}H_{34}O_2(l)+\frac{51}{2}O_2(g)\rightarrow 18CO_2(g)+17H_2O(g);\Delta H^o=-1.11\times 10^4kJ](https://tex.z-dn.net/?f=C_%7B18%7DH_%7B34%7DO_2%28l%29%2B%5Cfrac%7B51%7D%7B2%7DO_2%28g%29%5Crightarrow%2018CO_2%28g%29%2B17H_2O%28g%29%3B%5CDelta%20H%5Eo%3D-1.11%5Ctimes%2010%5E4kJ)
Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as ![\Delta H^o](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo)
The equation used to calculate enthalpy change is of a reaction is:
![\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%5Eo_f%28product%29%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%5Eo_f%28reactant%29%5D)
The equation for the enthalpy change of the above reaction is:
![\Delta H^o_{rxn}=[(18\times \Delta H^o_f_{(CO_2(g))})+(17\times \Delta H^o_f_{(H_2O)})]-[(1\times \Delta H^o_f_{(C_{18}H_{34}O_2(l))})+(\frac{51}{2}\times \Delta H^o_f_{(O_2(g))})]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%2818%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28CO_2%28g%29%29%7D%29%2B%2817%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28H_2O%29%7D%29%5D-%5B%281%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28C_%7B18%7DH_%7B34%7DO_2%28l%29%29%7D%29%2B%28%5Cfrac%7B51%7D%7B2%7D%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28O_2%28g%29%29%7D%29%5D)
We are given:
![\Delta H^o_f_{(CO_2(g))}=-393.51kJ/mol\\\Delta H^o_f_{(H_2O(g))}=-241.82kJ/mol\\\Delta H^o_f_{(O_2)}=0kJ/mol\\\Delta H^o_{rxn}=-1.11\times 10^4kJ](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_f_%7B%28CO_2%28g%29%29%7D%3D-393.51kJ%2Fmol%5C%5C%5CDelta%20H%5Eo_f_%7B%28H_2O%28g%29%29%7D%3D-241.82kJ%2Fmol%5C%5C%5CDelta%20H%5Eo_f_%7B%28O_2%29%7D%3D0kJ%2Fmol%5C%5C%5CDelta%20H%5Eo_%7Brxn%7D%3D-1.11%5Ctimes%2010%5E4kJ)
Putting values in above equation, we get:
![-1.11\times 10^4=[(18\times (-393.51))+(17\times (-241.82))]-[(1\times \Delta H^o_f_{(C_{18}H_{34}O_2(l))})+(\frac{51}{2}\times 0)]\\\\\Delta H^o_f_{(C_{18}H_{34}O_2(l))}=-94.12kJ/mol](https://tex.z-dn.net/?f=-1.11%5Ctimes%2010%5E4%3D%5B%2818%5Ctimes%20%28-393.51%29%29%2B%2817%5Ctimes%20%28-241.82%29%29%5D-%5B%281%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28C_%7B18%7DH_%7B34%7DO_2%28l%29%29%7D%29%2B%28%5Cfrac%7B51%7D%7B2%7D%5Ctimes%200%29%5D%5C%5C%5C%5C%5CDelta%20H%5Eo_f_%7B%28C_%7B18%7DH_%7B34%7DO_2%28l%29%29%7D%3D-94.12kJ%2Fmol)
Hence, the heat of formation of oleic acid is -94.12 kJ/mol
Molar mass of aluminum = 26.982 g/mol.
1 mol of Al = 26.9≈27g = 6.02×10²³ atoms [ avogadro's number]
meaning
1 g | Al = 6.02/27 × 10²³ atoms
so 3.78g | Al = 6.02×3.78]/27 ×10²³
= 0.8428 ×10²³ atoms
= 8.428 ×10²² atoms
Answer:
for the first question, the context is necessary in order to answer...
Fat is immiscible (does not mix) with water because fat is nonpolar and water is polar (remember like dissolves like: polar mixes with polar, nonpolar with nonpolar).
soap bubbles by having many soap molecules surround fat molecules with their nonpolar end, and direct their polar ends outwards.
For your second question:
Dirt and oil are nonpolar. When we wash our bodies with water (which is polar) it does not do a good job in removing these nonpolar molecules. Soap, on the other hand, has a long nonpolar end and a small polar end. The nonpolar end of the soap molecule attaches to the dirt and oil on your skin and when the water from the shower head hits the soap, it pulls the dirt, oil, and soap off of you by attaching itself to the polar end of the soap molecule.
Explanation: