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uysha [10]
3 years ago
8

How many aluminum atoms are in 3.78 g of aluminum?

Chemistry
1 answer:
____ [38]3 years ago
4 0
Molar mass of aluminum = 26.982 g/mol.
1 mol of Al = 26.9≈27g = 6.02×10²³ atoms [ avogadro's number]
meaning
1 g | Al = 6.02/27 × 10²³ atoms
so 3.78g | Al = 6.02×3.78]/27 ×10²³
= 0.8428 ×10²³ atoms
= 8.428 ×10²² atoms
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7 0
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