<span>Define a Potassium Reaction: A Potassium Reaction involves a process in which Potassium is mixed with another substance which react to form something else. Reactions are manifested by the disappearance of properties characteristic of Potassium and the appearance of new properties in the new substance or Compound. The substances initially involved in a reaction are called reactants or reagents. The most important of the Potassium compounds is Potassium chloride (KCl) which is used in the production of fertilizers and chemicals and also as a salt substitute. Other important compounds are Potassium nitrate (KNO3), also known as saltpeter which is used in the production of gunpowder, fertilizers and pyrotechnics and Potassium hydroxide (KOH) is used to make detergents and soaps. Reactions are described with Chemical Formula and Equations.</span>
Answer:
130
Explanation:
This is because that 3atm of N2O4 is used up for the 6atm of NO2, so 1 atm N2O4 is left. Resulting in In(1/4).
Answer:
D. concentration, as the concentrations of reactants and products remain unchanged after equilibrium is reached.
Explanation:
I put it for the test and i got right hehe
<span>The chemical properties of elements is determined by the electron shell configurations of each element. Different electron shell configuration = different chemical properties. And the number of electrons that an element has is determined by the number of protons the element has in it's nucleus. Iron has 26 protons, so a neutral atom of iron will have 26 electrons, while nickle has 28 protons, therefore when neutral will have 28 electrons. And since they have differing numbers of electrons, their electron shells differ and therefore their chemical properties differ.</span>
Answer:
The answer to your question is: 70.7 %
Explanation:
Equation
Xe + 2F₂ ⇒ XeF₄
limiting reactant = Xe
Xe is the limiting reactant because the ratio is:
theoretical = 131/ 76 = 1.72 g
experimental ratio = 130/100 = 1.3 the amount of F increased.
131.3 g of Xe ------------------ 207 g of XeF₄
130 g of Xe ------------------- x
x = (130 x 207) / 131.3
x = 205 g of XeF₄
% yield = 145 / 205 x 100
% yield = 70.7
