Answer:
15%
Explanation:
From the question given above, the following data were obtained:
Mass of sugar = 15 g
Mass of water = 85 g
Percentage of sugar in the solution =?
Next, we shall determine the mass of the solution. This can be obtained as follow:
Mass of solute (sugar) = 15 g
Mass of solvent (water) = 85 g
Mass of solution =?
Mass of solution = mass of solute + mass of solvent
Mass of solution = 15 + 85
Mass of solution = 100 g
Finally, we shall determine the percentage of the sugar in the solution. This can be obtained as follow:
Mass of solute (sugar) = 15 g
Mass of solution = 100 g
Percentage of sugar in the solution =?
Percentage = solute /solution × 100
Percentage = 15 / 100 × 100
Percentage of sugar in the solution = 15%
<h3>
Answer:</h3>
3.33 mol H₂O
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
60.0 g H₂O (Water)
<u>Step 2: Identify Conversions</u>
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
<u>Step 3: Convert</u>
- Set up:

- Multiply:

<u>Step 4: Convert</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
3.32963 mol H₂O ≈ 3.33 mol H₂O
Answer:
Aluminum atomic number= 13
electron configuration = 2, 8 , 3
Hope it helps...........
Answer:
100.14°C
Explanation:
The boling point elevation is a colligative property that describes the increasing in boiling point of a solution regard to the boiling point of the pure solvent. The equation is:
ΔT = Kf*m*i
<em>Where ΔT is boiling point elevation</em>
<em>Kf is boiling point elevation (0.51°C/m for water)</em>
<em>m is molality of the solution (7moles Ba(NO3)2 / 75kg = 0.09333m</em>
<em>i is Van't Hoff factor = 3 for Ba(NO3)2 (Because its dissolution produce 3 ions = Ba²⁺ and 2 NO₃⁻</em>
<em />
Replacing:
<em> </em>ΔT = 0.51°C/m*0.09333m*3
ΔT = 0.14°C is the boiling point elevation
As the boiling point of water is 100°C, the boiling point of the solution is:
100°C + 0.14°C =
<h3>100.14°C</h3>
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