Given:
Be - Beryllium - 9,3227
C - Carbon - 11,2603
O - Oxygen - 13,6181
Ne - Neon - 21,5645
B - Boron - 8,298
Li - Lithium - 5,3917
F - Fluorine - 17,4228
N - Nitrogen - 14,5341
Arranged from highest ionization energy to lowest ionization energy.
Ne ; F ; N ; O ; C ; Be ; B ; Li
Answer:
Weigh less than 61.9 g
Explanation:
The symbol V represents the element Vanadium and He represents Helium.
Generally, 1 mol of any atom contains 6.022 * 10^23 atoms. This means we have to find the number of moles of each elements.
For V;
Number of moles = Mass / Molar mass = 61.9 / 50.94 = 1.215 mol
1 mol = 6.022 * 10^23 atoms
1.215 = x
Number of atoms = 6.022 * 10^23 * 1.215 =7.317 * 10^23
For He;
Since equal number of moles contain equal number of atoms;
Number of mol of He = 1.215 mol
Number of moles = Mass / Molar mass
Mass = Molar mass * Number of moles = 4 * 1.215 = 4.86 g
This means it would weigh less.
Answer:
-145.2kJ
Explanation:
Enthalpy is an extensive property as its value depends on the amount of substance present in the system.
If the enthalpy for one mole of methanol = -726 kJ/mol;
The Enthalpy for 0.2 mol is given as;
Enthalpy = 0.200 * 726
Enthalpy = -145.2kJ
It would take -145.2kJ for 0.200 mol of methanol to undego the combustion reaction.
Answer:
cannot be broken down further
Answer: The molecular weight of tris buffer is 121 g/mol
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
where,
n = moles of solute
= volume of solution in L
moles of tris buffer =
Now put all the given values in the formula of molality, we get
Therefore, the molecular weight of tris buffer is 121 g/mol