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Llana [10]
2 years ago
14

How do Nitrate levels vary between tap water bottled water distilled water and outdoor water?

Chemistry
1 answer:
Ganezh [65]2 years ago
8 0
  • The key difference between tap water and distilled water is that tap water may contain impurities whereas distilled water does not contain impurities. Water covers more than 70% of the earth' surface. Thus, there is less than 1% of water left for direct human use.

<h2>HOPE IT HELPS!</h2>

#BrainlyFast

#MakethisBrainliestAnswer

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Trans fats: Think about how the prefix trans- is used in naming alkenes.
wel
In an alkene, cis and trans isomers are possible because the double band is rigid, cannot rotate, has groups attached to the carbons of the double bond that are fixed relative to each other, and only occurs with double bonds-possibility that molecule will have different geometries; two different molecules with slightly different properties. 
-Trans-2 ends of chain across the double bond.
While naming Cis-Trans isomers the prefix cis or trans are placed in front of the alkene name when there are cis-trans isomers. 
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2 years ago
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1. How many moles of oxygen are made if 12.0 moles of potassium chlorate react?
Alex787 [66]

Answer:

18

Explanation:

12*3=36

36/2=18

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2 years ago
Name the homologous series for this compound and show its structure<br>ch3ch2cc(ch2)2ch3​
kotykmax [81]

Answer:

Alkyne

Explanation:

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2 years ago
What volume (mL) of the partially neutralized stomach acid was neutralized by NaOH during the titration? (portion of 25.00 mL sa
almond37 [142]

The question is incomplete, here is the complete question:

What volume (mL) of the partially neutralized stomach acid having concentration 2 M was neutralized by 0.1 M NaOH during the titration? (portion of 25.00 mL NaOH sample was used; this was the HCl remaining after the antacid tablet did it's job)

<u>Answer:</u> The volume of HCl neutralized is 1.25 mL

<u>Explanation:</u>

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of stomach acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=2M\\V_1=?mL\\n_2=1\\M_2=0.1M\\V_2=25mL

Putting values in above equation, we get:

1\times 2\times V_1=1\times 0.1\times 25\\\\V_1=\frac{1\times 0.1\times 25}{1\times 2}=1.25mL

Hence, the volume of HCl neutralized is 1.25 mL

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3 years ago
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