How many atoms are in 0.100 mol of C3H8
1 answer:
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45 moles of H₂ are theoretically needed to produce 30.0 moles of NH₃
<h3>Further explanation</h3>Stoichiometry in Chemistry learn about chemicals mainly emphasizes quantitative, such as the calculation of volume, mass, number, which is related to numbers, molecules, elements, etc.
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.
In the reaction there are also manifestations of reagent substances namely gas (g), liquid (liquid / l), solid (solid / s) and solution (aqueous / aq).
The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.
- Mole
The mole itself is the number of particles contained in a substance amounting to 6.02.10²³
Mole can also be sought if the amount of substance mass and its molar mass is known
Reaction that happens :
N₂ +3H₂ ⇒ 2NH₃
mole N₂ : H₂ : NH₃ = 1 : 3 : 2
To produce 30.0 moles of NH₃,
- H₂ needed :
mole H₂ = 45 mole
- N₂ needed :
mole N₂ = 15 mole
So the minimum N₂ needed is: 15 mole
14.5 moles of N₂ can only produce NH₃ :
mole NH₃ = 29 mole
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Keywords: mole, NH₃, N₂, H₂
3.47 x atoms of gold have mass of 113.44 grams.
Explanation:
Data given:
number of atoms of gold = 3.47 x
mass of the gold in given number of atoms = ?
atomic mass of gold =196.96 grams/mole
Avagadro's number = 6.022 X
from the relation,
1 mole of element contains 6.022 x atoms.
so no of moles of gold given =
0.57 moles of gold.
from the relation:
number of moles =
rearranging the equation,
mass = number of moles x atomic mass
mass = 0.57 x 196.96
mass = 113.44 grams
thus, 3.47 x atoms of gold have mass of 113.44 grams