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3 years ago

Balancing Equations. How many of the element should I drag to the center?

Chemistry

1 answer:

Maurinko [17]3 years ago

5 0

Answer:

2, 6, 1

Explanation:

Ag3N is dissolved into Ag and N2. Since N2 is a molecule, there should be two Ag3Ns.

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Suppose that one of millikan's oil drops has a charge of −4.8×10−19

svlad2 [7]

The best and correct option is c

8 0

3 years ago

Read 2 more answers

Given KNO3 + CuSO4 is a double replacement reaction, predict the products and then determine whether you would expect to see a p

slava [35]

Answer:

Products will be K2SO4 and Cu(NO3)2. A precipitate will not form.

Explanation:

Double replacement reactions are the switching of cations between two compounds. So in this case, the K+ and Cu 2+ cations will switch places.

KNO3 + CuSO4 -> K2SO4 + Cu(NO3)2

According to solubility rules, any substances containing NO3 or a Group 1 ion (K+ in this case) will be definitely soluble. There are a few exceptions to the Group 1 rule but it does not apply here. Potassium sulfate (K2SO4) contains a Group 1 ion so it will be soluble and not be a precipitate. And copper nitrate (Cu(NO3)2) contains nitrate so it will also be soluble and not be a precipitate.

4 0

3 years ago

Two samples of the same compound are compared. what does the data represent? sample 1: 24.22 g carbon and 32.00 g oxygen sample

goblinko [34]

According to law of definite proportion:

In a compound, elements are always arranged in fixed ratio by mass.

Here, sample 1 has 23.22 g Carbon and 32.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

$n_{C}=\frac{m_{C}}{M_{C}}=\frac{24.22 g}{12 g/mol}\approx 2 mol$

Similarly, number of moles of oxygen will be:

$n_{O}=\frac{m_{O}}{M_{O}}=\frac{32 g}{16 g/mol}=2 mol$

The ratio of number of moles of carbon and oxygen will be:

$C:O=n_{C}:n_{O}=2:2=1:1$

Therefore, formula of compound will be CO.

Sample 2:

It has 36.22 g Carbon and 48.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

$n_{C}=\frac{m_{C}}{M_{C}}=\frac{36.22 g}{12 g/mol}\approx 3 mol$

Similarly, number of moles of oxygen will be:

$n_{O}=\frac{m_{O}}{M_{O}}=\frac{48 g}{16 g/mol}=3 mol$

The ratio of number of moles of carbon and oxygen will be:

$C:O=n_{C}:n_{O}=3:3=1:1$

The formula of compound will be CO.

Therefore, it is proved that carbon and oxygen are present in fixed ratios in both the samples.

4 0

3 years ago

2Na+S→Na2S

Sedbober [7]

Answer:

2.0 moles S

Explanation:

To find the number of moles of S, you need to convert the moles Na to moles S via the mole-to-mole ratio. This ratio is represented by the coefficients in the balanced equation. Because you wish to find moles S, you want to put this number in the numerator. Because you want to eliminate the moles Na, this number should be in the denominator.

2 Na + 1 S ---> Na₂S

4.0 moles Na 1 mole S
---------------------- x --------------------- = 2.0 moles S
2 moles Na

3 0

2 years ago

Please help! What is the molarity of 450 mL of solution containing 15 g NaCl?

siniylev [52]

Answer:

The answer to your question is 0.6 M

Explanation:

Data

Molarity = ?

Volume = 450 ml

mass of NaCl = 15 g

Process

1.- Calculate the molar mass of NaCl

NaCl = 23 + 35.5 = 58.5 g

2.- Calculate the number of moles of NaCl

58.5 g of NaCl ------------ 1mol

15 g of NaCl ------------ x

x = (15 x 1)/58.5

x = 0.26 moles

3.- Calculate the molarity

Molarity = moles/volume

-Substitutiion

Molarity = 0.26/0.45l

-Result

Molarity = 0.6 M

7 0

4 years ago