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Zielflug [23.3K]
3 years ago
12

Simplify the expression,cos x cotx + sinx​

Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
8 0

Answer:

cosec x

Step-by-step explanation:

\cos  x \:  \cot x +  \sin  x \\  \\  = \cos  x  \times  \frac{\cos  x }{ \sin  x }  +  \sin  x   \\  \\  = \frac{\cos^{2}  x +\sin^{2}  x }{ \sin  x }  \\  \\  = \frac{1}{ \sin  x }  \\  \\  = cosec x \\  \\   \red{ \boxed{ \bold{\therefore \:  \cos  x \:  \cot x +  \sin  x = cosec \: x}}}

blondinia [14]3 years ago
3 0

Answer:

csc x in edge

Step-by-step explanation:

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add the term that makes the given expression into a perfect square. write the result as the square of a bracketed expression c s
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<h2>Perfect Squares</h2>

Perfect square formula/rules:

  • a^2+2ab+b^2=(a+b)^2
  • a^2-2ab+b^2=(a-b)^2

Trinomials are often organized like ax^2+bx+c.

The <em>b</em> value in this case is <em>c</em>, and it will always equal the square of half of the <em>b</em> value.

  • Perfect square trinomial: ax^2+bx+(\dfrac{b}{2})^2
  • or ax^2-bx+(\dfrac{b}{2})^2

<h2>Solving the Question</h2>

We're given:

  • c^2-4c

In a trinomial, we're given the ax^2 and bx values. <em>a</em> in this case is 1 and <em>b</em> in this case is 4. To find the third value by dividing 4 by 2 and squaring the quotient:

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Therefore, the term that we can add is + 4.

c^2-4c+4

To write this as the square of a bracketed expression, we can follow the rule a^2-2ab+b^2=(a-b)^2:

(c-2)^2

<h2>Answer</h2>

c^2-4c+4

(c-2)^2

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