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Sophie [7]
3 years ago
15

What did Rutherford discover about the structure of the atom

Physics
1 answer:
AfilCa [17]3 years ago
7 0
He <span>discovered atom is composed from a central part - a nucleus, positively charged, surrounded by electrons - very small negative charged particles. </span>
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Chris is about to do an experiment to measure the density of water at several temperatures. His teacher has him prepare and sign
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Inspect the glassware for cracks or chips prior to beginning the lab.
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1. Give three examples, from the lab, where potential energy was converted to kinetic energy: ​
Lubov Fominskaja [6]

Answer:

A book on a table before it falls.

A yoyo before it is released.

A raised weight.

Explanation:

These are all examples of potential energy. So I hope you can find something that is comparable from the lab.

3 0
3 years ago
A subway train accelerates from rest at one station at a rate of 1.30 m/s^2 for half of the distance to the next station, then d
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This problems a perfect application for this acceleration formula:

         Distance = (1/2) (acceleration) (time)² .

During the speeding-up half:     1,600 meters = (1/2) (1.3 m/s²) T²
During the slowing-down half:    1,600 meters = (1/2) (1.3 m/s²) T²

Pick either half, and divide each side by  0.65 m/s²: 

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                         T = square root of (1600 / 0.65) seconds

Time for the total trip between the stations is double that time.

                         T =  2 √(1600/0.65) = <em>99.2 seconds</em>  (rounded)


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3 years ago
What is the difference between the hegelian right, center, and left? islamic?
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The main difference between<span> the two is that Enlightenment rationalism dwells in abstract inwardness. and it is only through this echo that German Christianity is ...</span>
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3 years ago
A small airplane takes on 302 l of fuel. If the density of the fuel is 0.821 g/ml, what mass of fuel has the airplane taken on?
ella [17]

To calculate the mass of the fuel, we use the formula

m = V \times  \rho

Here, m is the mass of fuel, V is the volume of the fuel and its value is V =302 \ L =  302 \ L \times \frac{10^{3}m L }{L} = 302 \times 10^{3} \ mL and  \rho is the density and its value of  0.821 g/mL.

Substituting these values in above relation, we get  

m = 302 \times 10^{3} \ mL \times 0.821 g/mL = 247942 g \\\\ m = 247. 94 \ kg

Thus, the mass of the fuel 247 .94 kg.

8 0
3 years ago
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