Answer:
find the diagram in the attachment.
Explanation:
Let vi = 12 m/s be the intial velocy when the ball is thrown, Δy be the displacement of the ball to a point where it starts returning down, g = 9.8 m/s^2 be the balls acceleration due to gravity.
considering the motion when the ball thrown straight up, we know that the ball will come to a stop and return downwards, so:
(vf)^2 = (vi)^2 + 2×g×Δy
vf = 0 m/s, at the highest point in the upward motion, then:
0 = (vi)^2 + 2×g×Δy
-(vi)^2 = 2×g×Δy
Δy = [-(vi)^2]/2×g
Δy = [-(-12)^2]/(2×9.8)
Δy = - 7.35 m
then from the highest point in the straight up motion, the ball will go back down and attain the speed of 12 m/s at the same level as it was first thrown
a.
The equivalent resistance of a series combination of two resistors is equal to the sum of the individual resistances:
In this circuit, we have
Therefore, the equivalent resistance is
b. 5.8 V, 3.2 V
First of all, we need to determine the current flowing through each resistor, which is given by Ohm's law:
where V = 9.00 V and . Substituting,
Now we can calculate the potential difference across each resistor by using Ohm's law again:
A plane mirror is a highly polished flat surface with a very high capacity to reflect incident light.
We can understand in a better way how this works with the figure attached:
1. The incident rays coming from the real object reach the mirror and
2.are reflected following the law of Reflection.
3.The prolongation of those reflected rays converge at a point that does not coincide with the actual position of the object. At that point the virtual image of the object is formed.
4.Then, the reflected divergent rays are captured by our eye converging on the retina.
Now, the image is said to be virtual because it is a copy of the object that looks as if the object is behind the mirror and not in front of it or on the surface, but it is not really there. However, it can be seen when we focus it with our eyes.
In addition, the image formed is:
symmetrical, because apparently it is at the same distance from the mirror
the same size as the object.
upright, because it retains the same orientation as the object.
