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svetoff [14.1K]
3 years ago
7

You walk 60m east and then 20m at 20 degrees south of west. What is your displacement?

Physics
1 answer:
stich3 [128]3 years ago
5 0
Let north and east be posetive
Y=20sin20
=6.840402867 south
X=20cos20
18.79385243 west
Net horizontal components=60+(-18.79)
=41.20614758m
Net vertical=-6.84040267
X^2=41.20614758^2+(-6.684040267)^2
√x^2 =√1744.73771m
x=41.77m
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During an auto accident, the vehicle’s air bags deploy and slow down the passengers more gently than if they had hit the windshi
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Answer:

d = 0.38 m

Explanation:

As we know that the person due to the airbag action, comes to a complete stop, in 36 msec or less, and during this time, is decelerated at a constant rate of 60 g, we can find the initial velocity (when airbag starts to work), as follows:

vf = v₀ -a*t  

If vf = 0, we can solve for v₀:

v₀ = a*t = 60*9.8 m/s²*36*10⁻³s = 21.2 m/s

With the values of v₀, a and t, we can find Δx, applying any kinematic equation that relates all of some of these parameters with the displacement.

Just for simplicity, we can use the following equation:

vf^{2} -vo^{2} = 2*a*d

where vf=0, v₀ =21.2 m/s and a= -588 m/s².

Solving for  d:

d = \frac{-vo^{2}}{2*a} = \frac{(21.2m/s)^{2} }{2*588 m/s2} =0.38 m

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