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creativ13 [48]
3 years ago
15

A power source of 6.0 V is attached to the ends of a capacitor. The charge is 12 C.

Physics
1 answer:
brilliants [131]3 years ago
5 0
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3) What is the weight of an object with a mass of 5.2 kilograms?​
inna [77]

Answer:

50.96 N

Explanation:

weight = mass x gravity

We know that gravity = 9.8 m/s^2 and mass = 5.2 kg.

w = m x g

w = 5.2 kg x 9.8 m/s^2

w = 50.96 N

The weight of the object is 50.96 N (newtons). Hope this helps, thank you !!

8 0
3 years ago
At which location would an objects weight be the greatest. 1.pluto 2.earth 3.sun 4.moon
Maslowich

Weight of the object is given as

Weight = mg

so weight of the object will be maximum where gravity(g) will be maximum

so here out of all given four the gravity "g" will be maximum at the surface of SUN as we know that sun will be of maximum mass out of all four planets

as we know that

g = \frac{GM}{R^2}

so correct answer will be

3. SUN

8 0
4 years ago
Read 2 more answers
Ice floats on water because ice is less dense than water. How is this helpful to fish that live in a lake?. . A.It shades the fi
Phantasy [73]
"It <span>keeps the fish warm in the winter" is the choice among the choices given in the question that shows how it is helpful to fish that lives in a lake water. The correct option among all the options that are given in the question is the second option or option "B". I hope the answer has helped you.</span>
3 0
3 years ago
Read 2 more answers
A 66-kg fellow stands on a digital scale in an elevator that accelerates upwards from rest to 4.5 m/s in 2.00 s. show answer Inc
Nina [5.8K]

Answer:

Explanation:

mass of the fellow ( m ) = 66kg

acceleration of fellow a

v = u + at

4.5 = 0 + a x 2

a = 4.5 /2

= 2.25 m / s²

Net force acting on fellow in upward direction by the surface of  elevator

R - mg where R is reaction force of the surface of the elevator

Applying Newton's law of motion

R - mg = ma

R = m (g +a )

= 66 x ( 9.8 + 2 )

= 778.8 N

This will be the scale reading .

7 0
3 years ago
the Latent heat of fusion of aluminum is 93 KCAL / kg at 660 degrees Celsius determine the amount of energy needed to melt 100 k
True [87]

Answer: 9300 kcal

Explanation: Given: Latent heat of fusion of aluminum is 93 kcal/kg.

That is for melting 1 kg of aluminium at 660^0C amount of heat required is = 93kcal

Thus for 100 kg of aluminium at 660^0C amount of heat required is= \frac{93}{1}\times 100=9300kcal

Thus the amount of energy needed to melt 100 kg of aluminum at the melting point is 9300 kcal.


8 0
3 years ago
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