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Nikitich [7]
3 years ago
5

I need help and I don't understand if you can help me but let it be before 6:00

Physics
1 answer:
viva [34]3 years ago
3 0

Answer:

balanced: a train moving at a constant speed, the moon orbiting the earth at a constant speed, a lamp sitting on a desk, an apple hanging on a tree

unbalanced: a skier coming down a mountain, a car accelerating from the start line, a soccer ball after it was kicked, a parachuter falling to ground

Explanation:

all the balanced ones are either moving at a constant speed or are skill

all the unbalanced ones were disturbed by some sort of force causing them to accelerate, go faster, blah blah blah

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A 50 kg person receives an absorbed dose of gamma radiation of 20 millirads. What is the total energy absorbed?.
Masteriza [31]

For a 50 kg person receives an absorbed dose of gamma radiation of 20 millirads,  the total energy absorbed is mathematically given as

E=0.1457J

<h3>What is the total energy absorbed?</h3>

Generally, the equation for the total energy absorbed  is mathematically given as

E=mass*gamma radiation

Therefore

E=50*20*19^{-3}

E=0.1457J

In conclusion,  the total energy absorbed

E=0.1457J

Read more about Energy

brainly.com/question/13439286

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2 years ago
Humans sleep in cycles, usually two or three cycles per night. There is a point in each cycle when waking up will leave the slee
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3 years ago
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For exercise, an athlete lifts a barbell that weighs 400 N from the ground to a height of 2.0 m in a time of 1.6 s. Assume the e
Sati [7]

Answer:

Explanation:

(ΔK + ΔUg + ΔUs + ΔEch + ΔEth = W)

ΔK is increase in kinetic energy . As the athelete is lifting the barbell at constant speed change in kinetic energy is zero .

ΔK = 0

ΔUg  is change in potential energy . It will be positive as weight is being lifted so its potential energy is increasing .

ΔUg = positive

ΔUs is change in the potential energy of sportsperson . It is zero since there is no change in the height of athlete .

ΔUs = 0

ΔEth is change in the energy of earth . Here earth is doing negative work . It is so because it is exerting force downwards and displacement is upwards . Hence it is doing negative work . Hence

ΔEth = negative .

b )

work done by athlete

= 400 x 2 = 800 J

energy output = 800 J

c )

It is 25% of metabolic energy output of his body

so metalic energy output of body

= 4x 800 J .

3200 J

power = energy output / time

= 3200 / 1.6

= 2000 W .

d )

1 ) Since he is doing same amount of work , his metabolic energy output is same as that in earlier case .

2 ) Since he is doing the same exercise in less time so his power is increased . Hence in the second day his power is more .

5 0
4 years ago
Frank stands still while throwing a dart toward a target with a speed of 25 m/s.
fgiga [73]

ANSWER IS A)

THE SPEED IS 25 M/S FOR BOTH PEOPLE

9 0
3 years ago
Next, given the equivalent resistance,
Tju [1.3M]

Answer:

reg21

Explanation:

because i said so

7 0
3 years ago
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