Answer:
1.4 kg of candy
Step-by-step explanation:
Divide the amount of candy by the number of jars:
12.58/9
= approx. 1.4
So, each jar will have approximately 1.4 kg of candy
Answer:
![\theta=36.43^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D36.43%5E%7B%5Ccirc%7D)
Step-by-step explanation:
Given that,
Base = 42
Perpendicular height = 31
We need to find the value of
. It can be calculated using trigonometry as follows :
![\tan\theta=\dfrac{P}{B}\\\\\theta=\tan^{-1}(\dfrac{P}{B})](https://tex.z-dn.net/?f=%5Ctan%5Ctheta%3D%5Cdfrac%7BP%7D%7BB%7D%5C%5C%5C%5C%5Ctheta%3D%5Ctan%5E%7B-1%7D%28%5Cdfrac%7BP%7D%7BB%7D%29)
Put all the values,
![\theta=\tan^{-1}(\dfrac{31}{42})\\\\\theta=36.43^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D%5Ctan%5E%7B-1%7D%28%5Cdfrac%7B31%7D%7B42%7D%29%5C%5C%5C%5C%5Ctheta%3D36.43%5E%7B%5Ccirc%7D)
So, the value of
.
Answer:
0.875
Step-by-step explanation:
look at the fraction as a division problem
8÷7
Answer:
![\vec v = 2\cdot \vec a = \langle -4,6 \rangle](https://tex.z-dn.net/?f=%5Cvec%20v%20%3D%202%5Ccdot%20%5Cvec%20a%20%3D%20%5Clangle%20-4%2C6%20%5Crangle)
Step-by-step explanation:
Let
, we need to determine
, which can be found by applying the following property:
,
(1)
Then,
![\vec v = 2\cdot \langle -2,3 \rangle](https://tex.z-dn.net/?f=%5Cvec%20v%20%3D%202%5Ccdot%20%5Clangle%20-2%2C3%20%5Crangle)
![\vec v = \langle -4,6 \rangle](https://tex.z-dn.net/?f=%5Cvec%20v%20%3D%20%5Clangle%20-4%2C6%20%5Crangle)
Answer:
small=15 large=40
Step-by-step explanation:
x=large box
y=small box
55 = x + y
50x + 55y = 2825
50x + 55( 55 - x) = 2825
50x + 3025 - 55x = 2825
0 = 55x - 50 x + 2825 - 3025
0 = 5x - 200
200 = 5x
x=40
y = 15