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IRINA_888 [86]
3 years ago
6

Write an inequality.

Mathematics
1 answer:
lukranit [14]3 years ago
5 0

Answer:

C ≥ 35/100c  

Step-by-step explanation:

c ≥ 35%/100c

Sorry I don't know if this is right but it's my guess.

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1) If y = x3 + 2x and dx/ dt = 5, find dy/dt when x = 2. Give only the numerical answer. For example, if dy, dt = 3, type only 3
Semenov [28]

Answer:

a) 70

b) 10π ft²/ft

c) 0.24 ft/sec

Step-by-step explanation:

1) y = x³ + 2x

\frac{dy}{dt}=\frac{d(x^3+2x)}{dt}

or

\frac{dy}{dt} = 3x^2\frac{dx}{dt}+2\frac{dx}{dt}

at \frac{dx}{dt}=5  and x = 2

\frac{dy}{dt} = 3(2)^2\times(5)+2\times(5)

or

\frac{dy}{dt} = 60 + 10 = 70

2) A = πr² ft²

\frac{dA}{dr}=\frac{d(\pi r^2)}{dr}

or

\frac{dA}{dr}= 2(πr)

at r = 5 ft

\frac{dA}{dr}= 2(π × 5) ft²/ft

or

\frac{dA}{dr}= 10π ft²/ft

3) From Pythagoras theorem

Base² + Perpendicular² = Hypotenuse²

Thus,

B² + P² = H²  .............(1)

here, H = length of the ladder

P is the height of the wall

B is the distance from the wall at bottom

or

B² + P² = 25²       ...........(1)  

at B = 20 ft

20² + P² = 25²        

or

P² = 625 - 400

or

P = √225

or

P = 15 ft

differentiating (1) with respect to time, we get

2B\frac{dB}{dt}+2P\frac{dP}{dt}=0

at B = 20 ft, \frac{dB}{dt} = 0.18 and P = 15 ft

⇒ 2(20)(0.18) + 2(15)\frac{dP}{dt} = 0

or

30\frac{dP}{dt} = - 7.2

or

\frac{dP}{dt} = - 0.24 ft/sec (Here negative sign depicts the ladder slides down)

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