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Ostrovityanka [42]
3 years ago
9

Find the greatest common factor of the following monomials 39a6b2 6a2b3

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
3 0
<span>39a⁶b² and 6a²b³ 
</span>39a⁶b² =3*13a⁶b² = 3*13a²a⁴b² =(3a²b²)*13a⁴
6a²b³ =2*3*a²b³ =2*3*a² *b*b²=(3a²b²)*2b
so (3a²b²) is the greatest common factor
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If we run the following line:<br> y = int(3 * '4')<br><br> what is the value of y?
Hitman42 [59]

The value of y in the code segment is 444

<h3>How to determine the value of y?</h3>

The code segment is given as:

y = int(3 * '4')

Evaluate the expression in the bracket

y =int('444')

Remove the bracket

y = 444

Hence, the value of y in the code segment is 444

Read more about code segments at:

brainly.com/question/26683418

#SPJ1

3 0
2 years ago
Thaddeus shakes his head as he pays $12.37 to the clerk for lunch. Complaining to a friend, Thaddeus says, “Do you realize that
atroni [7]

a)

his income must be "x" which is the 100%, and we would know that 0.2% of that is 12.37.

\begin{array}{ccll} amount&\%\\ \cline{1-2} x&100\\ 12.37&0.2 \end{array}\implies \cfrac{x}{12.37}=\cfrac{100}{0.2}\implies 0.2x=1237 \\\\\\ x=\cfrac{1237}{0.2}\implies x=61.85

b)

his income must be "x" which is the 100%, and we would know that 2% of that is 12.37.

\begin{array}{ccll} amount&\%\\ \cline{1-2} x&100\\ 12.37&2 \end{array}\implies \cfrac{x}{12.37}=\cfrac{100}{2}\implies 2x=1237 \\\\\\ x=\cfrac{1237}{2}\implies x=618.5

btw he's not making much either way.

7 0
2 years ago
Help me with number 3 please
Harlamova29_29 [7]
The answer would be 22%
6 0
3 years ago
the sum of age of mabel and fred is 38 years,four years ago the age of mabel was the square of Fred age.Find their ages
Andrej [43]

m+f=38

(f-4)^2=m-4

f^2=m IF their age is 30 combined

4^2=16

16=16

Fred is 4, Mabel is 16.

8 0
3 years ago
The table below shows the numbers of tickets sold at a movie theater on Friday.
sleet_krkn [62]

Answer:

Number of Adult's tickets sold on Saturday = 3,356

Number of Children's tickets sold on Saturday = 2, 928

Total number of tickets sold over these two days is 8,938.

Step-by-step explanation:

Here, the number of tickets sold on FRIDAY:

Adult Ticket sold = 1,678

Children's Tickets sold = 976

So, the total number of tickets sold on Friday  

= Sum of ( Adult + Children's ) tickets  = 1,678  + 976 = 2,654 ....  (1)

The number of tickets sold on SATURDAY:

Adult Ticket sold =   2 times as many as the number of adult tickets sold

on Friday

=  1,678 x 2  = 3,356

Children's Tickets sold = 3 times as many as the number of children's

tickets sold on Friday.

=  976  x 3 = 2, 928

So, the total number of tickets sold on Saturday  

= Sum of ( Adult + Children's ) tickets  = 3,356 + 2,928 = 6, 284 ....  (2)

Now, the total number of tickets booked in these two days :

Sum of tickets booked on (Friday + Saturday)

= 2,654 +  6, 284  =   8,938

Hence, total number of tickets sold over these two days is 8,938.

7 0
3 years ago
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