Find the greatest common factor of the following monomials 39a6b2 6a2b3

1 answer:

3 0

39a⁶b² and 6a²b³
39a⁶b² =3*13a⁶b² = 3*13a²a⁴b² =(3a²b²)*13a⁴
6a²b³ =2*3*a²b³ =2*3*a² *b*b²=(3a²b²)*2b
so (3a²b²) is the greatest common factor

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