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Alex Ar [27]
3 years ago
11

The are of a rectangle room is 80 square feet. I’f the length of one side of the room is 8 feet, what is the perimeter of the ro

om ?
Mathematics
1 answer:
leonid [27]3 years ago
7 0
The answer is 36. I know this because since one of the lengths of the room is 8, you take 80 and divide it by 8 which gives you 10. So now that you know the two side lengths you add. 10+10+8+8 which is 36.
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(-3/2)x - 9 = - 27 solve for x
aleksklad [387]

Answer:

x = 12

Step-by-step explanation:

Solve for x:

(-3 x)/2 - 9 = -27

Put each term in (-3 x)/2 - 9 over the common denominator 2: (-3 x)/2 - 9 = (-18)/2 - (3 x)/2:

(-18)/2 - (3 x)/2 = -27

(-18)/2 - (3 x)/2 = (-3 x - 18)/2:

(-3 x - 18)/2 = -27

Multiply both sides of (-3 x - 18)/2 = -27 by 2:

(2 (-3 x - 18))/2 = -27×2

(2 (-3 x - 18))/2 = 2/2×(-3 x - 18) = -3 x - 18:

-3 x - 18 = -27×2

2 (-27) = -54:

-3 x - 18 = -54

Add 18 to both sides:

(18 - 18) - 3 x = 18 - 54

18 - 18 = 0:

-3 x = 18 - 54

18 - 54 = -36:

-3 x = -36

Divide both sides of -3 x = -36 by -3:

(-3 x)/(-3) = (-36)/(-3)

(-3)/(-3) = 1:

x = (-36)/(-3)

The gcd of -36 and -3 is -3, so (-36)/(-3) = (-3×12)/(-3×1) = (-3)/(-3)×12 = 12:

Answer:  x = 12

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Step-by-step explanation:

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