The value of the power (-8) ti the second power is
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Answer:
Two non zero vectors, a and b are parallel when they are scalar multiples of each other such that a = c·b where c is a scalar quantity.
Therefore, in order to find a vector that is parallel to the vector, b = (-2, -1), we multiply the vector, b by a scaler quantity
Step-by-step explanation:
Given that the vector b = (-2, -1) can be written as follows;
b = -2·i - j, we have;
= √((-2)² + (-1)²) = √5
Therefore, we have;
The coordinates of the endpoint of the vector are (-2, 0) and (0, -1)
Therefore, the slope of the vector = (-1 - 0)/(0 - (-2)) = -1/2
The slope of parallel vectors are equal, which gives the slope of the parallel vector = -1/2 = (λ × (-1 - 0))/(λ ×(0 - (-2))
Therefore, a parallel vector is obtained from a vector by multiplying with a scaler product.