Answer:
https://revisionmaths.com/gcse-maths-revision/shape-and-space/vectors
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Co-interior properties. 180 degrees = two co-interior angles.
180 = (2y+50) + (3y+40)
180 = 5y + 90
90 = 5y
/5 /5
18 = y
Angle 1: 2y + 50
2(18) + 50
36 + 50
86
Angle 2: 3y + 40
3(18) + 40
54 + 40
94
86 + 94 = 180 so it is true.
Now the sides.
On a parallelogram, 5x+2 and 8x-7 must be equal
5x + 2 = 8x - 7
2 = 3x - 7
9 = 3x
/3 /3
3 = x
Side 1: 5x + 2
5(3) + 2
15 + 2
17
Side 2: 8x - 7
8(3) - 7
24 - 7
17
Both sides are equal; 17.
Angle 1: 86
Angle 2: 94
Sides: 17
Answer:
x = 10/9
Step-by-step explanation:
Solve for x:
(4 x)/5 + 4/3 = 2 x
Put each term in (4 x)/5 + 4/3 over the common denominator 15: (4 x)/5 + 4/3 = (12 x)/15 + 20/15:
(12 x)/15 + 20/15 = 2 x
(12 x)/15 + 20/15 = (12 x + 20)/15:
(12 x + 20)/15 = 2 x
Multiply both sides by 15:
(15 (12 x + 20))/15 = 15×2 x
(15 (12 x + 20))/15 = 15/15×(12 x + 20) = 12 x + 20:
12 x + 20 = 15×2 x
15×2 = 30:
12 x + 20 = 30 x
Subtract 30 x from both sides:
(12 x - 30 x) + 20 = 30 x - 30 x
12 x - 30 x = -18 x:
-18 x + 20 = 30 x - 30 x
30 x - 30 x = 0:
20 - 18 x = 0
Subtract 20 from both sides:
(20 - 20) - 18 x = -20
20 - 20 = 0:
-18 x = -20
Divide both sides of -18 x = -20 by -18:
(-18 x)/(-18) = (-20)/(-18)
(-18)/(-18) = 1:
x = (-20)/(-18)
The gcd of 20 and -18 is 2, so (-20)/(-18) = (-(2×10))/(2 (-9)) = 2/2×(-10)/(-9) = (-10)/(-9):
x = (-10)/(-9)
Multiply numerator and denominator of (-10)/(-9) by -1:
Answer: x = 10/9
Answer:
24
Step-by-step explanation:
-3(1(-8))
1x(-8) = -8
-3 x -8 =24
Answer:
2 - 2 cos²x = sin x
2 = sin x + 2 cos² x
0 = -2 + sin x + 2(1 - sin² x)
0 = -2 sin² x + sin x + 2 - 2
0 = 2 sin² x - sin x 0 = sin x (2 sin x - 1)
sin x = 0 v sin x = 0.5
x10° + k.360° x1 = 0°, 360°
x2 = (180° - 0°) + k.360°
x2 = 180°
x3 = 30° + k.360°
x3 = 30°
x4 = (180° -30°) + k.360° x4 = 150°
HP: {x | 0°, 30°, 150°, 180°, 360°)
