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viktelen [127]
3 years ago
7

Give the sum in simplest form: a/c + b/c = _____

Mathematics
1 answer:
djverab [1.8K]3 years ago
6 0

Answer:

(a+b)/c

Step-by-step explanation:

a/c+b/c

since they have the same denominator you can add the numerator together

(a+b)/c

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Which number line represents the solution set for the inequality -1/2 > 4
m_a_m_a [10]

Answer:

the first one

Step-by-step explanation:

5 0
3 years ago
HELP YOU WILL GET BRAINLIST
aksik [14]

Answer:

it is the blue box (not teal)

64 x 7/4 is less than 64 because 7/4 > 1

Hope this helps :)

4 0
3 years ago
What is the value of f(−3) for each function?1.
Hatshy [7]

Answer:

1. -21

2 . 14

3. -5

sorry if I'm wrong

Step-by-step explanation:

1. f(x) = 4 (-3) -9

f(x) = -12 - 9

f(x) = -21

2. f(x) = 1/3(-3) +13

f(x) = 1 + 13

3. f(x) = -2 (-3) -11

f(x) = 6 - 11

8 0
3 years ago
For the triangles to be congruent by hl, what must be the value of x? 8 9 17 34
lora16 [44]

Using equations we know that the value of x needs to be (E) 4 to make HL congruent to AC.

<h3>What are equations?</h3>

A mathematical equation is a formula that uses the equals sign to represent the equality of two expressions.

The point-slope form, standard form, and slope-intercept form are the three main types of linear equations.

So, HL is a hypotenuse that will be congruent to the hypotenuse AC.

We know that HL is 3x + 3.

Ac is 15.

Then the equation will be:

3x + 3 = 15

Now, solve the equation to get x as follows:

3x + 3 = 15

3x = 15 - 3

3x = 12

x = 12/3

x = 4

Therefore, the value of x needs to be (E) 4 to make HL congruent to AC.

Know more about equations here:

brainly.com/question/28937794

#SPJ4

Correct question:
For the triangles to be congruent by hl, what must be the value of x?

a. 8

b. 9

c. 17

d. 3

e. 4

8 0
1 year ago
Suppose M is the midpoint of FG. Find the missing measure.<br> MG = 13x + 1, FG = 15
Sholpan [36]

Answer:

14 - 13x

Step-by-step explanation:

take 13x + 1 away from 15

15 - (13x + 1) =  15 - 13x - 1  =  14 - 13x

4 0
3 years ago
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