Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Answer:12
Step-by-step explanation:
We can write a proportion to resemble the problem;
AE/ED = AB/BC
AE = 9
ED = 6
AB = x
BC = 10
Substitute with the given values.
9/6 = x/10
9/6 * 10 = x/10 * 10
90/6 = x
15 = x
Therefore, the answer is 15.
Best of Luck!
Answer:
I am not sure how your teacher wanted you to estimate the answer but I solved it for you. Hopefully this helps.
Step-by-step explanation:
7x-y=7
x+2y=6
14x-2y=14
x+2y=6
add both equations
15x=20
x=20/15
x=4/3
x+2y=6
4/3+2y=6
2y=6-4/3
2y=18/3 -4/3
2y=14/3
divide both sides by 2
y= 14/3 divided by 2
y=14/3(1/2)
y=14/6
2y=
