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Blababa [14]
3 years ago
9

Charlie wants to order lunch for his friends he'll order 6 sandwiches and a $2 kids meal for his little brother charlie has $32

how much can he spend on each sandwiches they are all the same price
choose two answer one for the inequality that models this sitiation and one for the correct answer ?

A.$13 or less
B.6x+2<32
C.$5 or less
D.2x+6<32
E.6x+2>32
F.2x+6<32
Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
3 0
Ill give u one its B because 6x where x is the price and 2 is the price for the kids meal and it needs to stay less than $32
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Kiera used place value and the distributive property to find the product of 12 and 597. Her work is shown below. 12(597) = 12(50
olya-2409 [2.1K]

Answer:

(90)(7) ⇒ the error was multiplying 90 and 7.


Step-by-step explanation:

12(597) = 12(500 + 90 + 7)

            = 12(500) + (90)(7)

             = 6000 + 630

                = 6,630

The part in bold shows where the error is. It was not correct to multiply 90 and 7.

The process was to proceed as follows:

12(597) = 12(500 + 90 + 7)

            = 12(500) + 12(90) + 12(7)

             = 6000 + 1080 + 84

                = 7,164

8 0
2 years ago
Help me put in those numbers down below
barxatty [35]
Box a should have 30 pieces of chocolate and box b should have 20 pieces of chocolate
5 0
3 years ago
Please help me!!
ipn [44]

{\color{chartreuse}{Measure\:of\: ∠\:on\: one\: side\:of\:line\:=\:180°}}

∠ Given are (x + 18)° , x° , 4x° and one Angle is 90° as per diagram

Let ,

1st∠ = (x + 18)°

2nd∠ = x°

3rd∠ = 4x°

so ,

⟶\:(x \:+\: 18)°\:+\:x°\:+\: 4x°\:+\:90°\:=\:180°

⟶\:6x°\:+ \:18°\:+\:90°\:=\:180°

⟶\:6x°\:+ \:108°\:=\:180°

⟶\:6x°\:=\:180°\:-\:108°

⟶\:6x\:=\:72°

⟶\:x\:=\:\frac{72}{6} \\

⟶\:x\:=\:12°

substituting x = 12 at the place of x .

= x° + 18°

= 12° + 18 °

1st∠ = 30°

__________________________________

= x°

2nd∠ = 12°

__________________________________

= 4x°

= 4(12)°

3rd∠ = 48°

7 0
2 years ago
2u + 1 &gt; -5/4u - 9<br><br> help please
FinnZ [79.3K]
2u + 1 > -5/4u - 9
2u + 5/4u > -9 - 1
8/4u + 5/4u > -10
13/4u > -10
u > - 10 * 4/13
u > -40/13 or - 3 1/13 <=
4 0
3 years ago
R=P over I squared. Solve for I.
kirza4 [7]

Answer: I=sqrt(P/R)

Step-by-step explanation:

R=p/I^2

Multiple l squared on both sides...

(I^2) R=p/l^2 (l^2)

R(I^2)=p

Separate I by dividing both sides by R...

I^2=p/R

Square root both sides...

I=sqrt(P/R)

6 0
3 years ago
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