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AlexFokin [52]
4 years ago
13

What is one common source of background radiation?

Physics
2 answers:
boyakko [2]4 years ago
7 0
One common source of background radiation would be radon. It is a radioactive gas<span> that emanates from the ground. </span><span>It is usually found in igneous rock and soil. Hope this answers the question. Have a nice day. Feel free to ask more questions.</span>
lapo4ka [179]4 years ago
5 0

Answer:

<h2>Cosmic radiation.</h2>

Explanation:

Background radiation is a measure of the ionizing radiation present in the environment. The most common source of this is cosmic radiation, which is formed by high energy sub-particles, which almost at light speed. All these particles come from the Sun and other stars, even from other galaxies.

In addition, another common source is the environmental radioactivity, which is produced by radioactive materials, some naturals, other by humans.

Therefore, the answer that best fit is <em>cosmic radiation. </em>

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Objects with masses of 130 kg and a 430 kg are separated by 0.300 m.(a) Find the net gravitational force exerted by these object
fredd [130]

Answer

given,

mass of object

m₁ = 130 Kg

m₂ = 430 Kg

distance between them = 0.3 m

a) net force when 35 kg is place in between them

   F = \dfrac{GMm}{R^2}

now,

   F = - \dfrac{6.67 \times 10^{-11}\times 130 \times 30}{0.15^2} +\dfrac{6.67 \times 10^{-11}\times 430 \times 30}{0.15^2}

   F = 3.12 \times 10^{-5}\ N

   Direction of force will be toward the mass of 430 Kg

b) position where force will be zero

 F =-\dfrac{6.67 \times 10^{-11}\times 130 \times 30}{(0.3-x)^2} +\dfrac{6.67 \times 10^{-11}\times 430 \times 30}{x^2} = 0

 -\dfrac{130}{(0.3-x)^2} +\dfrac{430}{x^2} = 0

 x^2- 0.6 x + 0.09=\dfrac{130}{430}x^2

 0.7 x^2- 0.6 x + 0.09 =0

solving the above equation

  x = 0.1936 m

the distance of third mass will be at x = 0.1936 m from 430 Kg mass.

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An uncharged 30.0-µF capacitor is connected in series with a 25.0-Ω resistor, a DC battery, and an open switch. The battery has
kolezko [41]

Answer:

(a) Maximum current through resistor is 1.43 A

(b) Maximum charge capacitor receives is 1.50\times 10^{-3}\text{ C}.

Explanation:

(a)

In an RC (resistor-capacitor) DC circuit, when charging, the current at any time, <em>t</em>, is given by

I(t) = I_0e^{-t/\tau}

Here, I_0 is the maximum current and <em>τ</em> represents time constant which is given by RC (the product of the resistance and capacitance).

The maximum current is given by

I = \dfrac{V}{R_\text{eff}}

<em>V</em> is the emf of the battery and R_\text{eff} is the effective resistance.

In this question, R_\text{eff} = 10.0 Ω + 25.0 Ω = 35.0 Ω

I = \dfrac{50.0\text{ V}}{35.0\ \Omega} = 1.43\text{ A}

(b) The maximum charge is given

<em>Q</em> = <em>CV</em>

where <em>C</em> is the capacitance of the capacitor

Q = (30.0\times10^{-6}\text{ F})(50.0\text{ V}) = 1.50\times 10^{-3}\text{ C}

3 0
4 years ago
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What types of natural phenomena could serve as time standards?
Delvig [45]

Answer: The rising and setting of the Sun.

The appearance and disappearance of the Moon.

Changes in season.

Appearance and disappearance of the Stars.

Explanation: The rising and setting of the Sun helps can be used as a standard to determine time since the rissing and setting of the Sun occurs at similar time and interval in a given geographical ocation.

The appearance and disappearance of the Moon which occurs during the night and early hours of the morning is similar in a given geographical locationation so it can be used as a standard for Time.

Change in season is another natural phenomenon which occurs at similar times in a given geographical location like Winter/summer, rainy/dry etc can be used as standards for time.

The appearance and disappearance of the Stars can also b used as standards for time in a given geographical location.

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4 years ago
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