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Sonja [21]
3 years ago
14

Kenya has a pile of salt on the counter. She uses a pinch of it for a meal. Which of the following physical properties of the sa

lt changes? 1.)Density 2.) Shape 3,) Solubility 4.)Thermal conductivity
Physics
1 answer:
Elodia [21]3 years ago
8 0

Answer:

The answer is shape.

Explanation: It says physical so it means the physical shape taking some of the salt would not change the density solubility or the Thermal conductivity

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Two charges, -20 C and +4.7 C, are fixed in place and separated by 3.0 m. a. At what spot along a line through the charges is th
Pani-rosa [81]

The zero net electric field point is at a point that is 0.98 m away from 4.7C charge.If a 14C charge is placed at this point then, force acted on the charge placed at this point is equal to zero.

Explanation:

Let at A both net electric field is zero then

At A ,E1=E2

E1=k*Iq1I / (d+x)^2

E2=k*Iq2I /x^2

Equating both

6 0
3 years ago
is set into oscillatory motion with an amplitude of 23.195 cm on a spring with a spring constant of 15.2676 N/m. The mass of the
fredd [130]

Answer:

maximum speed of the bananas is 18.8183 m/s

Explanation:

Given data

amplitude A =  23.195 cm

spring constant K = 15.2676 N/m

mass of the bananas m = 56.9816 kg

to find out

maximum speed of the bananas

solution

we know that radial oscillation frequency formula that is = √(K/A)

radial oscillation frequency = √(15.2676/23.195)

radial oscillation frequency is 0.8113125 rad/s

so maximum speed of the bananas = radial oscillation frequency × amplitude

maximum speed of the bananas = 0.8113125 × 23.195

maximum speed of the bananas is 18.8183 m/s

8 0
3 years ago
Which group of elements are shiny, opaque, and have a high melting point?
vlabodo [156]
The answer is A. Metals
3 0
3 years ago
Which statements best describe displacement? Check all that apply.
xxMikexx [17]

Answer:

the last one, the third one, and the first one.

8 0
2 years ago
Read 2 more answers
HELP PLEASE 20 POINTS SHOW WORK, ALL EQUATIONS
nataly862011 [7]

Answer:

s = 3 m

Explanation:

Let t be the time the accelerating car starts.

Let's assume the vehicles are point masses so that "passing" takes no time.

the position of the constant velocity and accelerating vehicles are

s = vt = 40(t + 2)  cm

s = ½at² = ½(20)(t)² cm

they pass when their distance is the same

½(20)(t)² = 40(t + 2)

10t² = 40t + 80

0 = 10t² - 40t - 80

0 = t² - 4t - 8

t = (4±√(4² - 4(1)(-8))) / 2(1)

t = (4± 6.928) / 2  ignore the negative time as it has not occurred yet.

t = 5.464 s

s = 40(5.464 + 2) = 298.564 cm

300 cm when rounded to the single significant digit of the question numerals.

7 0
3 years ago
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