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3 years ago

Help me please need answer and explained!!!!

Mathematics

2 answers:

Inga [223]3 years ago

7 0

Answer:

where is the question for us to answer?

Flauer [41]3 years ago

5 0

Whatchu need help with?

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Help!!!!!111! (picture shown) Math.... Help fast

Nana76 [90]

Answer:

Step-by-step explanation:

Hi,

2πr is the formula for circumference, you know your diameter is 4cm and radius is half of the diameter, so your radius is 2cm.

To find the circumference, you have to multiply 2 by 2 and pie. 2 x 2 is 4. So 4 times pie. B is your correct answer.

I hope this helps :)

7 0

3 years ago

If RS= 3x + 1 , ST= 2x -2 , RT= 64 , fine the value of x

Novay_Z [31]

The answer is

RS=3 x 2 + 1, ST= 2 x 4 -2, RT= 64, i'm sorry if it didn't help

6 0

4 years ago

Can somebody prove this mathmatical induction?

Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

$\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2$

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

3 step:

Check for n=k+1 whether the statement

$\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)$

is true.

Start with the left side:

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)$

According to the 2nd step,

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

Substitute it into the $\ast$

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)$

So, you have proved the initial statement

4 0

4 years ago

PLZ HRLO ME WITH THUA HARD QUESTIONS

love history [14]

It would be D hope this helps

8 0

3 years ago

Read 2 more answers

How many different ways can you make 75cents using nickles quaters and dimes?

kotegsom [21]

3 dimes, 1 nickel
2 dimes, 3 nickels
1 dime, 5 nickels
7 nickels
(don't forget to add in the initial quarter, dime, and nickel)

4 0

3 years ago