Sameee! I just wake up and I already wanna go take a nap lol
Answer:
R=0.0438 Ω
Explicación:
1) Hallar el área o sección del conductor de cobre, usando esta fórmula:
A=π.r² (Pi x radio al cuadrado)
Debido a que conocemos el diámetro (1.5mm) su radio es la mitad de esto es decir 0.75mm, y lo sustituimos en la fórmula:
A=π.(0.75mm)²
A=π(0.5625mm²)
A=1.7671mm²
2) La resistividad del cobre es: rho = 0,0172 y la incluimos en la fórmula siguiente:
R=p
R=0,0172Ω x
Simplificamos:
R=
El resultado es:
R=0.0438 Ω
Explanation:
This doesn't seem like a question -_-
0.29 M ammonia + 0.38 M ammonium bromide and 0.22 M hypochlorous acid + 0.18 M hydroiodic acids of aqueous solutions are good buffer systems.
<h3>Buffer Systems:</h3>
A solution that resists pH change when acids or bases are added to it is referred to as a buffer system. Either a weak acid and its salt, or a weak base and its salt, make up buffer systems. The ratio of HX/X- does not considerably alter when an acid or a base is introduced to a buffer.
Solutions known as buffers withstand pH changes when an acid or base is added. A weak base (A) and its conjugate weak acid (HA) are both present in buffers. When a reactive system is in equilibrium, adding a strong electrolyte with one common ion will cause the equilibrium to shift, lowering the concentration of the common ion. Buffers differ from one another in terms of pH range and buffer capacity.
Learn more about buffers here:
brainly.com/question/1385846
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