Answer:
Answers are in the explanation.
Explanation:
- The half‑life of A increases as the initial concentration of A decreases. order: <em>2. </em>In the half-life of second-order reactions, the half-life is inversely proportional to initial concentration.
- A three‑fold increase in the initial concentration of A leads to a nine‑fold increase in the initial rate. order: <em>2. </em>The rate law of second-order is: rate = k[A]²
- A three‑fold increase in the initial concentration of A leads to a 1.73‑fold increase in the initial rate. order: <em>1/2. </em>The rate law for this reaction is: rate = k √[A]
- The time required for [A] to decrease from [A]₀ to [A]₀/2 is equal to the time required for [A] to decrease from [A]₀/2 to [A]₀/4. order: <em>1. </em>The concentration-time equation for first-order reaction is: ln[A] = ln[A]₀ - kt. That means the [A] decreasing logarithmically.
- The rate of decrease of [A] is a constant. order: <em>0. </em>The rate law is: rate = k -<em>where k is a constant-</em>
Answer:
first u have to like draw like a number line uk how dey do in math but instead of num u add wht eva da question askin u
Explanation:
Answer:
Explanation:
Rate laws are mathematical expressions which define the relationship that exists between the rate of a chemical reaction and the concentration of the reacting components. Rate laws take the following form:
...
where k = rate constant
[A], [C] and [C] represent the molar concentrations of the reactants
k, x, y, and z are determined experimentally by observing how the rate of reaction changes with the concentrations of the reactants.
If x=1, the reaction is first order for [A]. Also, if y=2, the reaction is second order for [B] and so on...
The overall order of the reaction is the sum of the orders with respect to each reactant. Therefore, the overall order of the reaction is x+y+z.
Explanation:
we know that 0.250 L = 0.250 dm3
molarity = concentration in dm3/ volume
molarity = 0.175/0.250 = 0.7 mol/dm3