Answer:
33
Step-by-step explanation:
The product of the secant segment lengths is a constant.
... TC×CV = UC×CW
... 14(2x+2) = 12(2x+5) . . . . substitute the values from the diagram
... 28x +28 = 24x +60 . . . . eliminate parentheses
... 4x = 32 . . . . . . . . . . . . . . add -28-24x
... x = 8 . . . . . . . . . . . . . . . . divide by 4
UW = 12 + 2x + 5 = 17+2·8 . . . . UW = UC + CW
UW = 33
7+3t -t
------- = ----- is the relevant equation here. We don't ask, "What is 7+3t over
4 8 -t over 8," but rather "Solve the following equation for t."
Cross multiplying, 56 + 24t = -4t
-56
Then: 28t = 56, and t = ------ = -2 (answer)
28
The solution to "<span>What is 7+3t over 4 = -t over 8" is t = -2.</span>
Answer:
the answer is true
Step-by-step explanation:
9 = 2(6) - b
9 = 12 - b
-3 = b
Answer:
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Step-by-step explanation: