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Annette [7]
2 years ago
13

A clerical worker takes 4 times as long to finish a job as it does an executive secretary. Working together, it takes them 4 hr

to finish the job. How long
the clerical worker, working alone, to finish the job?

Mathematics
1 answer:
aleksandrvk [35]2 years ago
8 0

Answer:

\frac{5}{16} hours or 18\frac{3}{4} minutes

Step-by-step explanation:

\frac{1}{x} +\frac{1}{4x}= 4\\\\\frac{4}{4x}+\frac{1}{4x}   =4\\\\\frac{5}{4x} =4\\\\5=16x\\\\x=\frac{5}{16}

Calculating into minutes.

60*\frac{5}{16}=\\\\\frac{300}{16}  =\\\\18\frac{3}{4}

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3. Jim invests $3500, compounded annually at 12% for 3 years. What is the total
irga5000 [103]

Answer:

None of the above, it should be $4760

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 12%/100 = 0.12 per year,

then, solving our equation

I = 3500 × 0.12 × 3 = 1260

I = $ 1,260.00

The simple interest accumulated

on a principal of $ 3,500.00

at a rate of 12% per year

for 3 years is $ 1,260.00

3 0
2 years ago
Bishwant and sunayana cimplete a oiece of a work in 6 days working together.if bishwant alime can complete it n 10 days.in how m
alina1380 [7]

Step-by-step explanation:

sunaina's alona work=

1/6-1/10

10-6/60

4/60

1/15

therefore sunaina can alone do the work in 15 days

4 0
3 years ago
You are evenly dividing up 57 apples among 5 friends
tatiyna

Answer:

11.4 have a great day :)

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
I really need help on this im bad at math anyway but i cant see graphs clearly first good answer will get brainliest Please help
emmainna [20.7K]

\sin(b) =  \frac{3}{4} \\ b = inverse \: sine \: of \:  \frac{3}{4} = 48.6
7 0
3 years ago
Read 2 more answers
An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y
aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average time = 23.92 minutes

             s = sample standard deviation = 6.72 minutes

             n = sample of times = 40

             \mu = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u>\mu<u> is; </u>

P(-2.426 < t_3_9 < 2.426) = 0.98  {As the critical value of z at 1%  level

                                               of significance are -2.426 & 2.426}  

P(-2.426 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.426) = 0.98

P( -2.426 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

P( \bar X-2.426 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.426 \times {\frac{s}{\sqrt{n} } } , \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 23.92-2.426 \times {\frac{6.72}{\sqrt{40} } } , 23.92+2.426 \times {\frac{6.72}{\sqrt{40} } } ]  

                                    = [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0
2 years ago
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