Answer:
The vectors are linearly independent
Step-by-step explanation:
These vectors can be written in a matrix form as:
![\left[\begin{array}{ccc}5&-2&4\\2&-3&5\\4&5&-7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%26-2%264%5C%5C2%26-3%265%5C%5C4%265%26-7%5Cend%7Barray%7D%5Cright%5D)
and if the matrix is invertible, the system has a unique solution, and hence, the vectors that form the matrix are linearly independent.
A matrix is invertible if it's determinant is different from zero.
Suppose A is a matrix, A is invertible if |A| ≠ 0

= 
= ![= 5[-7(-3) - 5(5)] + 2[2(-7) - 4(5)] + 4[5(2) - 4(-3)]\\= 5(21 - 25) + 2( -14 -20) + 4(10 + 12)\\= 5(-4) + 2(-34) + 4(21)\\= -20 - 68 + 84\\= -4\\](https://tex.z-dn.net/?f=%3D%205%5B-7%28-3%29%20-%205%285%29%5D%20%2B%202%5B2%28-7%29%20-%204%285%29%5D%20%2B%204%5B5%282%29%20-%204%28-3%29%5D%5C%5C%3D%205%2821%20-%2025%29%20%2B%202%28%20-14%20-20%29%20%2B%204%2810%20%2B%2012%29%5C%5C%3D%205%28-4%29%20%2B%202%28-34%29%20%2B%204%2821%29%5C%5C%3D%20-20%20-%2068%20%2B%2084%5C%5C%3D%20-4%5C%5C)
Since this is not zero, we conclude that the vectors are linearly independent.