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Ahat [919]
3 years ago
11

Suppose an unknown radioactive substance produces 12800 counts per minute on a Geiger counter at a certain time, and only 800 co

unts per minute 10 days later. Assuming that the amount of radioactive substance is proportional to the number of counts per minute, determine the half-life of the radioactive substance.
Mathematics
1 answer:
suter [353]3 years ago
5 0

Answer:

2.5 days.

Step-by-step explanation:

The number of half lives  is n where

12800(0.5)^n = 800

12800(0.5)^4 = 800

so n = 4

So the half life is 10/4

= 2.5 days.

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If f(x) = x + 7 and g(x)=1/x, what is (f o g)(x)?
Black_prince [1.1K]

Answer: 1/x + 7

Step-by-step explanation: you plug the function g(x) into the function f(x) .. substitue g(x) for the x in f(x)

G(x) = 1/x , so you plug that in the x of f(x) and get 1/x + 7

8 0
3 years ago
The pair of points is on the graph of an inverse variation. find the missing value. (5,4) and (x,7)
d1i1m1o1n [39]
One form of the relation of inverse variation is y = k/x.

first step:  Find the value of k:    Taking the values x=5 and y = 4, 4=k/5, or k=20.  Then,   y = 20/x.

Next:  Let y = 7 and find the corresp. value of x:  7=20/x, or 7x=20, or

x = 20/7    (answer) 
7 0
3 years ago
Read 2 more answers
find the number of running and passing plays using substitution method 110 plays 3 yards per run 7 yards per pass total yards 37
Zinaida [17]

Let x be the number of running plays

Y  be the number of passing plays

Since the total plays is 110

 X + y = 110

And total yard is 378

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Using the first equation

X = 110 – y and substitute to the 2nd equation

3(110 – y) + 7y = 378

And solve for y

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7 0
3 years ago
What THREE integers have a sum of 300?
quester [9]

Answer:

Here we will use algebra to find three consecutive integers whose sum is 300. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 300. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 300

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 300

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3X + 3 - 3 = 300 - 3

3X = 297

3X/3 = 297/3

X = 99

Which means that the first number is 99, the second number is 99 + 1 and the third number is 99 + 2. Therefore, three consecutive integers that add up to 300 are 99, 100, and 101.

99 + 100 + 101 = 300

We know our answer is correct because 99 + 100 + 101 equals 300 as displayed above.

Step-by-step explanation:

8 0
3 years ago
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4y= -6x +8 <br>find the y-intercept
ivanzaharov [21]
First, divide each side by 4 to get y alone on the left side.

y=-6/4x+2

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7 0
3 years ago
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