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3 years ago

Need Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

ladessa [460]3 years ago

8 0

I'm not entirely sure since we didn't learn this in class yet but I would say that Linear Pair Postulate goes with the ABC=135. Which leaves the subtraction Property of Equality for the last one. The reasoning I have for choosing that answer is becasue it made the made the most sense to me becasue the problem gives us the Linear Pair Postulate for BCD and I just thought that ABC = 135 was the other Linear Pair Postulate.

kifflom [539]3 years ago

7 0

The firat box goes into the seond box and the second box goes into the first box

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Flora's Florist charges a standard delivery charge of

goldenfox [79]

Answer: $10.00 + 4.50r

r = rose

$10.00 = delivery charge

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2 years ago

Evaluate x-(-y)x−(−y)x, minus, left parenthesis, minus, y, right parenthesis where x = -2.31x=−2.31x, equals, minus, 2, point, 3

Angelina_Jolie [31]

Step-by-step explanation:

$x-(-y)=x+y\\\\\text{substitute}\ x=-2.31,\ y=5.9:\\\\-2.31+5.9=5.9+(-2.31)=5.9-2.31=5.90-2.31=3.59$

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3 years ago

Which strategy would you use to divide 36÷6?Explain why you chose that strategy.

marusya05 [52]

I would use what times 6 = 36 because 6*6+36

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3 years ago

Read 2 more answers

I NEED HELP ASAP!!!!

dedylja [7]

Answer:

B) 8

Step-by-step explanation:

Triangles MNC and RSC are similar because all 3 angles are the same, so the the ratio between each side should be the same.

If NC=12 and SC=6 then triangle MNC is scaled up by 2 from triangle RSC. This means each side of MNC is 2 times bigger than on RSC. So, sense RS=4, we can multiply that by 2 to get MN=8.

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2 years ago

Help ASAP!! See screenshot below.

Anika [276]

ANSWER

The relation is not a function.

EXPLANATION

The relation is not a function because we have an x-coordinate mapping on to more than one y-coordinate.

This occurs at x=1.

The ordered pairs (1,1) and (1,3) disqualify the relation from being a function.

Hence the relation is not a function.

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3 years ago