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tresset_1 [31]
3 years ago
7

Pleaseeee help geometry 14p!! Brainliest if correct!

Mathematics
1 answer:
Reika [66]3 years ago
4 0

It’s a hollow cylinder, since a rectangle rotated like that results in a cylinder. If that’s not a good explanation, then picture rotating it, and hopefully you’ll get it ♡

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\begin{aligned} &-5y=-5 \\\\ &7x+6y=7 \end{aligned}
SSSSS [86.1K]

Answer:

(5,1) is not a solution of the above system of equations.

Step-by-step explanation:

We are given a system of equations that are  

- 5y = - 5 ......... (1) and  

7x + 6y = 7 ........... (2)

So, solving equation (1) we get y = 1 and putting y = 1 in the equation (2) we get 7x = 7 - 6(1) = 1

⇒ x = \frac{1}{7}

So, it clear from the solution of the above equations i.e. (\frac{1}{7}, 1), we can say that (5,1) is not a solution of the above system of equations. (Answer)

7 0
4 years ago
It took Everly 55 minutes to run a 10-kilometer race last weekend. If you know that 1 kilometer equals 0.621 mile, how many minu
m_a_m_a [10]
55/6.21 = x/1....55 mins to 6.21 miles = x min to 1 mile
cross multiply
6.21x = 55
x = 55/6.21
x = 8.86 minutes
3 0
4 years ago
Read 2 more answers
Solve for X. Please help ASAP.
vfiekz [6]

Answer:

x = 36.87

Step-by-step explanation:

Find the length of the missing side.

x^2 + 12^2 = 15^2

x^2 + 144 = 225

x^2 = 81

x = 9

Now use the law of sines:

sin(90)/15 = sin(x)/9

Multiply each side by 9

9 * sin(90)/15 = sin(x)

0.6 = sinx

sin^-1 = 36.86989 rounded to 36.87

4 0
3 years ago
28 g of iron shot is added to a graduated cylinder containing 40cm of water. The water level rises to the 44cm mark. From this i
Aneli [31]

\huge\fbox{Answer ☘}

Volume of water displaced = Volume of shape

‎ ‎ ‎ ‎ ‎‎ ‎ ‎ ‎ ‎‎ ‎ ‎ ‎ ‎‎ ‎ ‎ ‎ ‎‎ ‎ ‎ ‎ ‎‎ ‎ ‎ ‎ ‎\bold{⇢ ( \:44 \:- \:40\: ) \:mL}\\\bold{⇢ 4 \:mL}

Weight = 28 g

\bold\blue{density =  \frac{mass}{volume}}  \\  \\ \pink{ ⇢ \cancel \frac{28}{4}  }\\  \\  \pink{⇢ 7 \: g \: ml {}^{ - 1}}

hope helpful ~

6 0
3 years ago
8<br> Express sin A, cos A, and tan A as ratios.<br> 12<br> 613
Evgen [1.6K]

Answer:

see explanation

Step-by-step explanation:

sinA = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{6\sqrt{3} }{12} = \frac{\sqrt{3} }{2}

cosA = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{6}{12} = \frac{1}{2}

tanA = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{6\sqrt{3} }{6} = \sqrt{3}

7 0
3 years ago
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