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3 years ago

Can someone please help ASAP

Mathematics

2 answers:

Talja [164]3 years ago

6 0

Answer:
6

how:
add up all the numbers the divide by the amount of numbers given.

Use:
First, I added all the numbers up and got 48.
Next, I divided by 8.
Last, I did 42 divided by 8 and got 6.
The mean is 6.

salantis [7]3 years ago

4 0

The answer is 6 (I’m pretty sure)

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How long will it take me to read 125 pages if I can read 20 pages in 30 minutes?

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2 years ago

Please help me with this math question I really need help ;/. I'll give brainliest if u help.

Darya [45]

Step-by-step explanation: You have to substitute the numbers in for x & y

(0, -5): YES

3x - 4y - 8 = 12

3(0) - 4(-5) - 8 = 12

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20 - 8 = 12

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(4, -2): YES

3x - 4y - 8 = 12

3(4) - 4(-2) - 8 = 12

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(8, 2): NO

3x - 4y - 8 = 12

3(8) - 4(2) = 12

24 - 8 = 12

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(-16, -17): YES

3x - 4y - 8 = 12

3(-16) - 4(-17) - 8 = 12

-48 + 68 - 8 = 12

20 - 8 = 12

12 = 12

(-1, -8): NO

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3(-1) - 4(-8) = 12

-3 + 32 = 12

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(-40, -34): NO

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2 years ago

The GCF of 18 and 27 is _______.

Gnoma [55]

Answer:

Step-by-step explanation:

The factors of 18 are : 1, 2, 3, 6, 9, 18

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2 years ago

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2 tan 30°<br>II<br>1 + tan- 300

shusha [124]

Question:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Answer:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

Simplify

In trigonometry:

$tan(30^{\circ}) = \frac{1}{\sqrt{3}}$

So, the expression becomes:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}$

Simplify the denominator

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} / \frac{4}{3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} * \frac{3}{4}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{1}{\sqrt 3} * \frac{3}{2}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3}$

Rationalize

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3\sqrt{3}}{2* 3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

In trigonometry:

$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

3 0

3 years ago