The equation of a circle is written as (x-h)^2 + (y-k)^2 = r^r
H and k are the x and y coordinates of the center of the circle and r is the radius.
You are given the diameter coordinates so find the halfway point for the center then calculate the radius
Midpoint = (x1 +x2)/2, (y1 + y2)/2
Midpoint = (7 + -1)/2, (-3 +7)/2
Midpoint = 6/2, 4/2
Midpoint = 3,2
So h = 3 and k = 2
Now find radius by finding the distance between the center point and an end point.
Distance = sqrt(41)
Equation of the circle:
(X-3)^2 + (y-2)^2 = 41
4,720 rounded to the nearest thousand is 5,000
4720 is closer to 5000 than it is to 4000.
The standard form equation for a circle is
where (h, k) is the center and r is the radius.
The standard form equation for an ellipse is
(center h, k and major and minor axes a and b)
This equation is standard form for neither, but might be general form for one.
Answer:
An angle is in standard position, if its vertex is located at the origin and one ray is on the positive x-axis.
Step-by-step explanation:
9514 1404 393
Answer:
D. 12
Step-by-step explanation:
There are a number of ways to find the area of this rectangle. Perhaps the most straightforward is to find the lengths of the sides and multiply those. The distance formula is useful.
d = √((x2 -x1)^2 +(y2 -y1)^2)
Using the two upper-left points, we find the length of that side to be ...
d = √((3 -0)^2 +(3 -0)^2) = √(9 +9) = √18 = 3√2
Similarly, the length of the lower-left side is ...
d = √((-2 -0)^2 +(-2 -0)^2) = √(4+4) = √8 = 2√2
Then the area of the rectangle is ...
A = LW
A = (3√2)(2√2) = 3·2·(√2)^2 = 3·2·2 = 12
The area of rectangle ABCD is 12.
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Other methods include subtracting the area of the corner triangles from the area of the bounding square:
5^2 -2(1/2)(3·3) -2(1/2)(2·2) = 25 -9 -4 = 12
