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Burka [1]
4 years ago
12

Which are dependent events? Check all that apply

Mathematics
2 answers:
sashaice [31]4 years ago
6 0

Answer:

whats the question dude

IRINA_888 [86]4 years ago
5 0

Answer:

choosing 2 socks from a drawer, without replacement

picking 4 cards from a deck one after the other

Step-by-step explanation:

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Choose the formula for the volume of a rectangular box, V = lwh written in terms of w.
lilavasa [31]

The width of the rectangular box will be 8cm

Given that the formula for calculating the volume of a rectangular box is expressed as:

V=lwh

L is the length

w is the width

h is the height

Get the "value of "w

V = lwh\\w=\frac{V}{lh}

Given the following parameters

Length l = 3 cm

Volume V = 120cm³

Height = 5cm

Get the width of the box as shown:

w=\frac{V}{lh}\\w=\frac{120}{3\times 5}\\w=\frac{120}{15}\\w=  8cm

Hence the width of the rectangular box will be 8cm

Learn more here: brainly.com/question/20415942

4 0
3 years ago
Find the diagonal of a square whose sides are of the given measure.<br> 7 square root of 3
Sholpan [36]
I encourage you to draw in the diagonal. The diagonal of a square will create a triangle with the sides of the square. Specifically, this is a right triangle as the angles of a square are right angles by definition.

Use the Pythagorean theorem: a^2 + b^2 = c^2. In this case, sides a and b are each 7sqrt(3), and c is the diagonal of the square.
a^2 + b^2 = c^2
(7sqrt3)^2 + (7sqrt3)^2 = c^2
294 = c^2
c = sqrt(294) = 7sqrt(6)
3 0
3 years ago
A college is creating a new rectangular parking lot. the length is 0.17 mile longer than the width and the area of the parking l
Svetradugi [14.3K]
Let's call the width of the parking lot w.
The length of the parking lot if .17 more than the width so the length is w + .17

The parking lot is rectangular so its area is found by multiplying the length and the width. That is, the area is equal to what we obtain when we multiply w by w+.17. The area is: A = w(w+.17)= w^{2} +.17w

We are also told that the area is equal to .039 square miles so we set the expression we obtained for the area equal to .039 as follows.

w^{2} +.17w=.039

Since w represents the width of the rectangular lot, we can solve this equation for w to find the width. This is a quadratic equation (the highest exponent of the variable w is 2). We solve these by setting them equal to zero and then using the quadratic formula.

Setting our equation equal to zero (subtract .039 from both sides) gives us:
w^{2} +.17w-.039=0

The quadratic formula is as follows. Since the equation is in terms of w we write it as "w = ..." instead of the usual "x = ..."

w= \frac{-bplusminus \sqrt{ b^{2} -4ac} }{2a}

The part I write as "plusminus" is typically written with a + sign over a - sign. For right now let's leave it at that. Later in the problem we will see what it means and what to do with it.

To use the formula we have to identify a, b and c.

a is the coefficient of the squared term. That is, the number in front of w^{2} which here is 1.

b is the coefficient of the linear term. That is, the number in front of w which here is .17

c is the constant (the number by itself0 which is -.039

So we have:
a=1
b=.17
c=-.039

We plug these into the quadratic formula to obtain:
w= \frac{-.17plusminus \sqrt{ .17^{2} -(4)(1)(-.039)} }{(2)(1)}
w= \frac{-.17plusminus \sqrt{ .0289+.156} }{2}
w= \frac{-.17plusminus \sqrt{ .189} }{2}
w= \frac{-.17plusminus.43} {2}

Here is where the "pluminus" comes in. We continue to simplify the expression on the right but we split it in two. In one case we use "plus" and in the other "minus". That is, we add in one and subtract in the other. This gives us:
w= \frac{-.17+.43}{2}= \frac{.26}{2}=.13
and
w= \frac{-.17-.43}{2}= \frac{-.6}{2}=-.3

w is the width of the rectangular lot so it is a distance and cannot be measured using negative numbers. The width of the rectangular must be positive so we disregard the negative answer.

The width of the rectangle is .13 miles

Recall that the length of the rectangle is .17 more than the width. That is, the length is w+.17 and as we know the width to be .13 miles the length is .13 + .17 = .3 miles

The answer therefore is:
width = .13 miles
length = .3


4 0
3 years ago
Read 2 more answers
What is the missing side of the missing triangle. Round your answer to the
Rashid [163]

Answer:

Step-by-step explanation:

√(7² + 2²) = √53 ≅ 7.28

7 0
3 years ago
(3x-3) (2x-1)<br> ill pay u ill bid if u want
bezimeni [28]

Answer: 6x^2 - 9x + 3

Step-by-step explanation:

first, i multiplied the parentheses.

3x x 2x - 3x - 3 x 2x - 3 x (-1)

then, i calculated/multiplied it.

6x^2 - 3x - 6x + 3

finally, i collected the like terms.

6x^2 - 9x + 3

3 0
3 years ago
Read 2 more answers
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