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3 years ago

In how many ways can the letters of the word ``COPYRIGHT'' be arranged?

Mathematics

1 answer:

PilotLPTM [1.2K]3 years ago

4 0

Answer:

362,880 ways

Step-by-step explanation:

There are 9 letters so 9!

And none of them are repeated so 9!/0!

9! = 362,880

I hope this helps, and plz mark me brainliest!!

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What number is 120% of 20?

Lera25 [3.4K]

I’m pretty sure is 14

7 0

3 years ago

Read 2 more answers

The polar form of this is?

prohojiy [21]

Answer:

2, 120 degrees

Step-by-step explanation:

The first step in finding the polar form is finding the modulus, r

r= sqrt( x^2 + y^2)

r = sqrt( (-1)^2 + sqrt(3)^2)

r = sqrt(1+3)

r= sqrt(4)

r =2

The next step is finding the angle

theta = arctan (y/x)

theta = arctan (sqrt(3)/-1))

theta = arctan (-sqrt(3))

theta = -60

The point (-1, sqrt(3)) is in the 2nd quadrant, but our angle is in the 4th quadrant, so we add 180 degrees

theta = -60 + 180 = 120

theta = 120 degrees

6 0

3 years ago

Please answer the question in the photo, thanks!

belka [17]

Answer:

$\therefore 2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}$

Step-by-step explanation:

The question relates to dividing a fraction by proper and another fraction

The given expression is presented as follows;

$2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right )$

We rearrange the fractions as improper fractions for easier division as follows;

$2\dfrac{1}{3} = \dfrac{7}{3}$

$-3\dfrac{2}{3} = -\dfrac{11}{3}$

Therefore, we have;

$2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right ) = \dfrac{7}{3} \div \left (-\dfrac{11}{3} \right ) = \dfrac{7}{3} \times \left (\dfrac{1}{-\dfrac{11}{3} } \right ) = \dfrac{7}{3} \div \left (-\dfrac{3}{11} \right ) =-\dfrac{7}{11}$

$\therefore 2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}$

4 0

2 years ago

What is (x^-2 y^10)^2/x^5 y^-3 using only positive exponents

Eddi Din [679]

Answer:

$\frac{(x^{ - 2}{y}^{10})^{2} }{ {x}^{5} {y}^{ - 3} } \\ \frac{ {x}^{ - 4} {y}^{20} }{ {x}^{5} {y}^{ - 3 } } \\ {x}^{ - 9} {y}^{23} \\ \frac{ {y}^{23} }{ {x}^{9} } \\ ans \: c$

8 0

2 years ago

According to the Fundamental Theorem of Algebra, which polynomial function has exactly 8 roots?

HACTEHA [7]

Answer:

Option (1)

Step-by-step explanation:

Fundamental theorem of Algebra states degree of the polynomial defines the number of roots of the polynomial.

8 roots means degree of the polynomial = 8

Option (1)

f(x) = (3x² - 4x - 5)(2x⁶- 5)

When we multiply (3x²) and (2x⁶),

(3x²)(2x⁶) = 6x⁸

Therefore, degree of the polynomial = 8

And number of roots = 8

Option (2)

f(x) = (3x⁴ + 2x)⁴

By solving the expression,

Leading term of the polynomial = (3x⁴)⁴

= 81x¹⁶

Therefore, degree of the polynomial = 16

And number of roots = 16

Option (3)

f(x) = (4x² - 7)³

Leading term of the polynomial = (4x²)³

= 64x⁶

Degree of the polynomial = 6

Number of roots = 6

Option (4)

f(x) = (6x⁸ - 4x⁵ - 1)(3x² - 4)

By simplifying the expression,

Leading term of the polynomial = (6x⁸)(3x²)

= 18x¹⁰

Degree of the polynomial = 10

Therefore, number of roots = 10

3 0

3 years ago