(2+6t)(2+6t)(2+6t)(2+6t)(2+6t)(2)=? (2+4t)(2+4t)(2+4t)(2+4t)(2+4t)(2)=?
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For this case we have the following function:
To find the zeros of the function we make and solve for "x", then:
We multiply by -1 on both sides of the equation:
We factor the equation, for this we look for two numbers that, when multiplied, result in 36 and when added, result in -13. These numbers are -9 and -4.
Thus, the factored equation is:
Therefore, the roots are:
Answer: