Y = mx + b. This linear graph passes through A(0,50) and B(10,51)
m = (y₂-y₁)/(x₂-x₁)
m= (51-50)/10-0)
m=(1)(10)
y = (1/x) + b. To find b, you plugin the coordinates of either A or B,
say A(0,50):
50 = (1/10).(0) + b
50 = 0+b and b= 51
Hence the equation is y =0.1x + 50
An acute angle can also be made inside of that type of triangle.
It would be 1/5, 5/8, 2/3 because 1/5 is 24/120, 2/3 is 80/125, and 5/8 is 75/120
