Answer:
<u><em>Similarity:</em></u>
In Both cosine and sine graphs, a positive and negative number vertically flips the graph and tells whether the graph starts at maximum (positive) or minimum (negative).
<u><em>Difference:</em></u>
The difference between the sine and the cosine graph is the point where they start.
The graph of positive cosine starts at the maximum while that of the negative cosine starts at the minimum.
The graph of a positive sine starts at the middle, goes up and then down while that of the negative sine starts at the middle goes down and then up.
Answer:
Step-by-step explanation:
a) A relation R is symmetric when it includes the inverse relation, for example if it includes (8,9) then it should also include (9,8), if not, then the relation is not symmetric, you can see that in this case the relation includes (3,4) but not (4,3), therefore it is not symmetric
b) A relation is antisymmetric when it never includes the inverse relation, for example if it includes (8,9) then it can not include (9,8), if it does then it is not antisymmetric. In this case you can see that it first starts with (1,2) but then it also includes (2,1) so then it is not antisymmetric
c) A relation is reflexive if for each number of the domain set it includes the pair that is two times that same number, for example if 8 is in the domain then the relation should include (8,8). if not then it is not reflexive. In this case you can see that the domain S includes 1 but (1,1) is never on the relation or for example (2,2) is also never in the relation.
Answer:
Gud morning friend
Step-by-step explanation:
Sorry friend I don't know
Answer:
625
Step-by-step explanation:
with long division, you just need to remember these five steps, divide, multiply, subtract, bring it down, and repeat.
hope this helps :3
if it did pls mark brainliest
Answer:
The values are calculated with the help of table.
Step-by-step explanation:
We are given the following information in the question:
A table is shown showing trees on two different plots of land which are tested for disease.
Tree: 1 2 3 4 5 6 7
Plot: A A B B B A B
Disease: Y N Y Y Y N N
We have to find:
Calculating from the table, we can fill the values as:
Plot A Plot B
Disease Present 1 3
Disease not Present 2 1
