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AfilCa [17]
3 years ago
5

Does changing the compound inequality x>-3 and x<3 from and to or change the solution set? Explain

Mathematics
2 answers:
Serggg [28]3 years ago
8 0

Answer:

So the answer is

Step-by-step explanation:

x)2943

aniked [119]3 years ago
3 0

Answer:The x values of the “and” inequality satisfy both inequalities.

The x values of the “or” inequality satisfy one or both inequalities.

Changing the compound inequality from “and” to “or” changes the solution set from the values between –3 and 3 for all real numbers.

Step-by-step explanation:

that's all u need

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alicia cashed her paycheck and used half of her earnings to take three friends to dinner. She spent $42.15 on dinner and she bro
Nana76 [90]
X - $42.15 > $20.00
<u>  + $42.15 + $42.15</u>
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5 0
3 years ago
The product of a binomial and a trinomial is x3+3x2-x+2x2+6x-2 Which expression is equivalent to this
solong [7]
The answer is the first one.
Explanation:
X^3 stays the same because there are no other cubed numbers in the problem
Next you combine the x^2s
The x^2s are +3x^2 and +2x^2
Since they are both positive, you add them: 3x^2 + 2x^2 = 5x^2
Next you do the x values
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Lastly, you just add in the -2 and get:
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8 0
2 years ago
90 hundreds = how many thousands
alina1380 [7]

we know that

90 hundreds=90*100\\ =9,000

and

one.thousand=1,000

So

Divide

9,000 by 1,000

\frac{9,000}{1,000} =9

therefore

the answer is

9

3 0
3 years ago
Read 2 more answers
A pack of 30 pencils cost $7.97 and a pack of 12 pencils cost $4.77. which is better? how do you know?
Black_prince [1.1K]

The better one is a pack 30 pencils that costs $7.97. How do I know I divide 7.97/30 and got 0.26567. I did the same thing to the other one and got 0.3975. The one that is smaller is the best one.

5 0
3 years ago
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Please help! ASAP I just need number 1
Goshia [24]

Answer:

no you can not make 1 into a triangle

Step-by-step explanation:

16 cm, 30 cm, 45 cm

if you want to draw a triangle with these sides you would add

16 + 30 = 46

the longest side would have to be greater then the other 2 sides

7 0
3 years ago
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