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3 years ago

How do you find the lowest common factor of 6 and 14

1 answer:

3 0

2 divides both numbers, so divide both numbers by 2 to get 3 and 7. These are relatively prime, so 2 is the gcd. The lcm is 6*14/2=42.

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3x squared - 2 x y when x=2 and y = 5

ira [324]

the Answer is 4 do order of operations

7 0

3 years ago

The lengths of two sides of a right triangle are 5 inches and 8 inches. What is the difference between the two possible

3241004551 [841]

Answer:

Option 2 - 3.2 inches.

Step-by-step explanation:

Given : The lengths of two sides of a right triangle are 5 inches and 8 inches.

To find : What is the difference between the two possible lengths of the third side of the triangle?

Solution :

According to question, it is a right angle triangle

Applying Pythagoras theorem,

$H^2=P^2+B^2$

Where, H is the hypotenuse the longer side of the triangle

P is the perpendicular

B is the base

Assume that H=8 inches and B = 5 inches

Substitute the value in the formula,

$8^2=P^2+5^2$

$64=P^2+25$

$P^2=64-25$

$P^2=39$

$P=\sqrt{39}$

$P=6.24$

Assume that P=8 inches and B = 5 inches

Substitute the value in the formula,

$H^2=8^2+5^2$

$H^2=64+25$

$H^2=89$

$H=\sqrt{89}$

$H=9.43$

Therefore, The possible length of the third side of the triangle is

$L=H-P$

$L=9.43-6.24$

$L=3.19$

Therefore, The difference between the two possible lengths of the third side of the triangle is 3.2 inches.

So, Option 2 is correct.

3 0

3 years ago

Read 2 more answers

Tanx cosx = 0

shtirl [24]

You're almost finished.

(sin/cos) times cos = 0

Look at the left side. You could write it as (sin x cos) / cos = 0
and simply divide numerator and denominator by the cosine (cancel it).

Then what do you have left ? . . . <u>sin(x) = 0</u> Do I need to finish this for you ?

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3 years ago

Review the diagram of a locket in the shape of an ellipse.

Helen [10]

Answer:

Step-by-step explanation:

If you graph y^2/361 + x^2/169=1 you will get the same graph depicted in the equation.

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3 years ago

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Prove that : <br><br>tan^2(theta) - tan^2(alpha) = sec^2(theta) - sec^2(alpha)

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