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Agata [3.3K]
3 years ago
14

Is 12 posters for 36 students equivalent to 21 posters to 63 student

Mathematics
2 answers:
Zanzabum3 years ago
7 0

Answer:

12 posters for 36 students equivalent to 21 posters to 63 student

Step-by-step explanation:

we need to check whether 12 posters for 36 students equivalent to 21 posters to 63 student

12 posters for 36 students can be written as \frac{12}{36} = \frac{1}{3}

Now 21 posters to 63 student can be written as

\frac{21}{63} divide top and bottom by 3

\frac{21}{63} = \frac{7}{21}=\frac{1}{3}

So, 12 posters for 36 students equivalent to 21 posters to 63 student

Dmitry [639]3 years ago
3 0

yes.

this is division. 36 divided by 12 is 3. 63 divided by 21 is 3.

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vlabodo [156]

Answer:

step 1

Find the average growth per year of the populations of rabbits farm A

Over the first 2 years

for t=0

numbers of rabbits=5 (is not exact)

for t=2

numbers of rabbits=40

average=[40-5]/2---------> 17.5

step 2

Find the average growth per year of the populations of rabbits farm B

Over the first 2 years

for t=0

numbers of rabbits=5 (is not exact)

for t=2

numbers of rabbits=30

average=[30-5]/2---------> 12.5

step 3

Compare the average growth per year of the populations of rabbits on both farms

farm A=17.5

farm B=12.5

the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 5 rabbits per year.

therefore

the answer is the option C)

the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 6 rabbits per year.

Step-by-step explanation:

6 0
2 years ago
Does the order in which you add two integers with the same sign affect the sum
kondor19780726 [428]
If you add positive 5 and positive 5, you'll get positive 10.
If you add positive 5 and negative 5, you'll get positive 0.
If you add negative 5 and negative 5, you'll get negative 10.

-5 + 5 = -5 + 5
5 + 5 = 5 + 5
- 5 + -5 = -5 + -5

Does that help your question?
6 0
3 years ago
Can anybody help me with this ?
frutty [35]

f(x) = (3/4)ˣ - 4

As x gets really negative (3/4)ˣ grows positively without bound (because it's (4/3)⁻ˣ and 4/3 > 1).

As x gets really positive (3/4)ˣ tends to zero but never quite gets there.

So (3/4)ˣ > 0 for all x

So f(x) > 0 - 4 for all x

Answer:  { y   | y > -4  }, first choice

7 0
3 years ago
Solve step by step solution then only i can do it plxx ​
Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So \triangle ABC and \triangle ABD Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
  • First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

  • We need to find base=b

According to Pythagoras thereon

{\boxed{\sf b^2=h^2-p^2}}

  • Substitutethe values

\longrightarrow\sf b^2=10^2-p^2

\longrightarrow\sf b={\sqrt {10^2-8^2}}

\longrightarrow\sf b={\sqrt{100-64}}

\longrightarrow\bf b={\sqrt {36}}

\longrightarrow\sf b=6

\therefore\overline{BC}=6cm

  • BD=BC+CD

\longrightarrowBD=9+6

\longrightarrowBD=15cm

  • Now in \triangle ABD

Perpendicular=p=8cm

Base =b=15cm

  • We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

{\boxed {\sf h^2=p^2+b^2}}

  • Substitute the values

\longrightarrow\sf h^2=8^2+15^2

\longrightarrow\sf h={\sqrt {8^2+15^2}}

\longrightarrow\sf h={\sqrt {64+225}}

\longrightarrow\sf h={\sqrt {289}}

\longrightarrow\sf h=17cm

\therefore{\underline{\boxed{\bf x=17cm}}}

3 0
3 years ago
The distance between city E and F is 678.35 miles and the distance between city F and G is 156.8 miles. What is the distance bet
Free_Kalibri [48]

E to F = 678.35 miles
F to G = 156.8 miles
G to H = x
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E to G = 678.35 + 156.8 miles
E to G = 835.15
G to H = 2,457 - 835.15
G to H = 1621.85 miles

8 0
3 years ago
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