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Taya2010 [7]
3 years ago
11

The asteroid ceres lies at an average distance of 414 million kilometers from the sun. The period of revolution of ceres around

the sun is approximately

Physics
2 answers:
nikitadnepr [17]3 years ago
8 0

Answer:

Answer is 1.156x10^23 sec

Explanation:

According to kepler's law, the square of the period of revolution is proportional to the cube of the distance within planets.

At a distance r of 414 million kilometers I.e 414x10^6 km, period calculation is shown in the image below.

7nadin3 [17]3 years ago
6 0

Answer:

T2 = 1680,4 days

Explanation:

Kepplers law:

\frac{T^{2} }{a^{3} }  = constant

For Earth:

T1 = 365 days ; a1 = 149 597 870 700 m

For Ceres:

T2 = ? days ; a1 = 414*10^{9}  m

Then:

\frac{T1^{2} }{a1^{3} }  = \frac{T2^{2} }{a2^{3} }  ----> T2 =  T1*\sqrt{\frac{a2^{3}}{a1^{3}}}

Replacing values:

T2 = 1680,4 days

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