An 800 kg car is parked next to a 1000 kg car. Their centers of mass are 3.5 m apart. Find the gravitational force between them.
1 answer:
Answer:
4.356e-6 Newtons
Explanation:
Using the equation for the force of gravity F=. The two masses are m1=800kg and m2=1000 kg. The value of G, the gravitational constant =6.67e-11. The problem states the distance between the center of masses of the two cars is 3.5 meters(r). Plugging in what we have from the problem, you will get 4.346e-6 newtons. This makes sense as gravity in itself is a weak force requiring extremely massive objects to result in a noticeable force.
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Answer:
a) Em₀ = 42.96 104 J
, b) = -2.49 105 J
, c) vf = 3.75 m / s
Explanation:
The mechanical energy of a body is the sum of its kinetic energy plus the potential energies it has
Em = K + U
a) Let's look for the initial mechanical energy
Em₀ = K + U
Em₀ = ½ m v2 + mg and
Em₀ = ½ 50.0 (1.20 102) 2 + 50 9.8 142
Em₀ = 36 104 + 6.96 104
Em₀ = 42.96 104 J
b) The work of the friction force is equal to the change in the mechanical energy of the body
= Em₂ -Em₀
Em₂ = K + U
Em₂ = ½ m v₂² + m g y₂
Em₂ = ½ 50 85 2 + 50 9.8 427
Em₂ = 180.625 + 2.09 105
Em₂ = 1,806 105 J
= Em₂ -Em₀
= 1,806 105 - 4,296 105
= -2.49 105 J
The negative sign indicates that the work that force and displacement have opposite directions
c) In this case the work of the friction going up is already calculated in part b and the work of the friction going down would be 1.5 that job
We have that the work of friction is equal to the change of mechanical energy
= ΔEm
= Emf - Emo
-1.5 2.49 10⁵ = ½ m vf² - 42.96 10⁴
½ m vf² = -1.5 2.49 10⁵ + 4.296 10⁵
½ 50.0 vf² = 0.561
vf = √ 0.561 25
vf = 3.75 m / s
The rate of fuel burning in grams per hour if the DT reaction is used is 1.08 × J/g per hour
<h3>How is the rate of fuel burning in grams per hour calculated when the D-T reaction is used?</h3>
- D + T → He + n
- The D-T fusion reaction results in a Helium (He) and neutron (n)
E = 17.59 MeV
Mass = 2.014u + 3.016u
= 5.030u
Energy per Kg = (17.59××1.6×
) ÷ ( 5.030×1.66×
)
= 3.37× J/Kg
= 3.0× J/g
Rate of fuel burning in grams per hour = 3.0× × 3600
= 3.6×3.0×
= 1.08 × J/g per hour
To learn more about fusion reactor and energy production, refer
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