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mr Goodwill [35]
3 years ago
6

An 800 kg car is parked next to a 1000 kg car. Their centers of mass are 3.5 m apart. Find the gravitational force between them.

Physics
1 answer:
adoni [48]3 years ago
4 0

Answer:

4.356e-6 Newtons

Explanation:

Using the equation for the force of gravity F=\frac{Gm_1m_2}{r^2}. The two masses are m1=800kg and m2=1000 kg. The value of G, the gravitational constant =6.67e-11. The problem states the distance between the center of masses of the two cars is 3.5 meters(r). Plugging in what we have from the problem, you will get 4.346e-6 newtons. This makes sense as gravity in itself is a weak force requiring extremely massive objects to result in a noticeable force.

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A 1000 kg car moving at 108 km/h jams on its brakes and comes to a stop. How much work was done by friction?
Nostrana [21]

Answer:

The work done by friction was -4.5\times10^{5}\ J

Explanation:

Given that,

Mass of car = 1000 kg

Initial speed of car =108 km/h =30 m/s

When the car is stop by brakes.

Then, final speed of car will be zero.

We need to calculate the work done by friction

Using formula of work done

W=\Delta KE

W=K.E_{f}-K.E_{i}

W=\dfrac{1}{2}mv_{f}^2-\dfrac{1}{2}mv_{f}^2

Put the value of m and v

W=0-\dfrac{1}{2}\times1000\times(30)^2

W=-450000
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W=-4.5\times10^{5}\ J

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3 years ago
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Brut [27]

Answer:

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Explanation:

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2 years ago
Why are latitude and longitude included on maps
Veseljchak [2.6K]

Answer:

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3 0
2 years ago
A spacecraft of mass 1500 kg orbits the earth at an altitude of approximately 450 km above the surface of the earth. Assuming a
PSYCHO15rus [73]

Answer:

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Let the acceleration due to gravity at this height is g'

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W = m x g' = 1500 x 8.55 = 1.28 x 10^4 N

8 0
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tia_tia [17]

Answer:

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