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Darina [25.2K]
4 years ago
6

What is 3x-8y=-17 y=4 in substitution

Mathematics
1 answer:
Murljashka [212]4 years ago
5 0
3x-8(4) =17
3x -32=17
3x=-49
x=16.3...
thats how you solve for x but Im not sure if that what you wanted
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Let a and b be roots of x² - 4x + 2 = 0. find the value of a/b² +b/a²​
erastovalidia [21]

Answer:

\dfrac{a}{b^2}+\dfrac{b}{a^2}=10

Step-by-step explanation:

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\begin{aligned}\implies x & =\dfrac{-(-4) \pm \sqrt{(-4)^2-4(1)(2)}}{2(1)}\\& =\dfrac{4 \pm \sqrt{8}}{2}\\& =\dfrac{4 \pm 2\sqrt{2}}{2}\\& =2 \pm \sqrt{2}\end{aligned}

\textsf{Let }a=2+\sqrt{2}

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\begin{aligned}\implies \dfrac{a}{b^2}+\dfrac{b}{a^2} & = \dfrac{2+\sqrt{2}}{(2-\sqrt{2})^2}+\dfrac{2-\sqrt{2}}{(2+\sqrt{2})^2}\\\\& = \dfrac{2+\sqrt{2}}{6-4\sqrt{2}}+\dfrac{2-\sqrt{2}}{6+4\sqrt{2}}\\\\& = \dfrac{(2+\sqrt{2})(6+4\sqrt{2})+(2-\sqrt{2})(6-4\sqrt{2})}{(6-4\sqrt{2})(6+4\sqrt{2})}\\\\& = \dfrac{12+8\sqrt{2}+6\sqrt{2}+8+12-8\sqrt{2}-6\sqrt{2}+8}{36+24\sqrt{2}-24\sqrt{2}-32}\\\\& = \dfrac{40}{4}\\\\& = 10\end{aligned}

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2 years ago
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If you add the price of the ticket and drink it comes out to 12.25, subtract from 25 and the answer is 12.75
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