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Maurinko [17]
3 years ago
12

WILL MARK BRAINLIEST!!!!!!!!!!!!!!!!!! Why would someone choose to use a graphing calculator to solve a system of linear equatio

ns instead of graphing by hand? Explain your reasoning.
Mathematics
2 answers:
Musya8 [376]3 years ago
7 0

Answer:

WHEN U GRAPH WITH A CALCULATOR  IT IS MUCH MORE ACCURATE

ESPECIALLY IF THERE R FRACTIONS AND DECIMALS AND THE GRAPHING CALCULATOR GOES ON FOREVER WHERE AS THE GRAPHING PAPER  ENDS

Step-by-step explanation:

HOPE I HELPED

PLS MARK BRAINLIEST

DESPERATELY TRYING TO LEVEL UP

          ✌ -ZYLYNN JADE ARDENNE

JUST A RANDOM GIRL WANTING TO HELP PEOPLE!

                                         PEACE!

ohaa [14]3 years ago
6 0

Answer:

A graphing calculator is more accurate than graphing by hand. If the slope and/or y-intercept is a fraction or decimal, it is more difficult to accurately graph by hand.

Step-by-step explanation:

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Solve the attached question<br><br>#yohaniJaman<br><br><br><br>​
aksik [14]

HETY is a parallelogram.

HT and EY are diagonals. We know that diagonals divides the parallelogram into two equal parts.

So ar(HET) = ar(HTY)

And, ar(HEY) = ar(EYT) now, in AHET, diagonal EY bisects the line segment HT and also the AHET,

∴ar(AHOE) = ar(AEOT)

Similarly in AETY

ar(ΔΕΟΤ) = ar(ΔΤΟΥ)

And in AHTY,

ar(ATOY) = ar(AHOY)

That means diagonals in parallelogram divides it into four equal parts.

Hence Proofed.

5 0
3 years ago
a sequence starts a 200 and 30 is subtracted each time 200,170,140 what are the first two numbers in the sequence that are kess
Snowcat [4.5K]
<h3>Answer:  -10 and -40</h3>

===============================================================

Explanation:

a = 200 = first term

d = -30 = common difference

Tn = nth term

Tn = a + d(n-1)

Tn = 200 + (-30)(n-1)

Tn = 200 - 30n + 30

Tn = -30n + 230

Set Tn less than 0 and isolate n

Tn < 0

-30n + 230 < 0

230 < 30n

30n > 230

n > 230/30

n > 7.667 approximately

Rounding up to the nearest whole number gets us n \ge 8

So Tn starts to turn negative when n = 8

We can see that,

Tn = -30n + 230

T7 = -30*7 + 230

T7 = 20

and

Tn = -30n + 230

T8 = -30*8 + 230

T8 = -10 is the 8th term

and lastly

Tn = -30n + 230

T9 = -30*9 + 230

T9 = -40 is the ninth term

Or once you determine that T7 = 20, you subtract 30 from it to get 20-30 = -10 which is the value of T8. Then T9 = -40 because -10-30 = -40.

5 0
3 years ago
Read 2 more answers
In ΔVWX, the measure of ∠X=90°, WX = 8.3 feet, and XV = 2.5 feet. Find the measure of ∠W to the nearest tenth of a degree.
kiruha [24]

Answer:

16.76°

Step-by-step explanation:

In ΔVWX, the measure of ∠X=90°, WX = 8.3 feet, and XV = 2.5 feet.

We want to find the measure of <W.

We know side length that is adjacent and opposite to <W.

We can use the tangent ratio, to find the measure of <W.

The tangent ratio is opposite over hypotenuse.

\tan(m \angle \: w)  =  \frac{2.5}{8.3}

\tan(m \angle \: w)  =  0.301

Take tangent inverse to get:

m \angle \: w= { \tan}^{ - 1}   (0.301)

m \angle \: w=16.76  \degree

7 0
3 years ago
(b) The force, F, between two objects is inversely proportional to the square of the distance, d, between
LiRa [457]

Answer:

F is reduced by 31%

Step-by-step explanation:

F = 1/(d²)

now, we increase the distance by 20% (multiply by 1.2).

F new = 1/(1.2×d)² = 1/(1.44×d²) = (1/1.44) × (1/(d²)) =

= 1/1.44 × old F = 0.69 × old F

100 - 69 = 31%

6 0
3 years ago
A regular octagon has an apothem of 16.9 cm and a side length of 14 cm. Find the area to the nearest tenth.
jolli1 [7]

Answer:

946.4 cm

Step-by-step explanation:

Formula for finding the area of any polygon :

number of sides (n) x 0.5 x length of sides (s) x apothem (a)

Area = 8 x 0.5 x 14 x 16.9 = 946.4

hope this helps ! :)

8 0
2 years ago
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