answer:
178.5398mm²
explanation:
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Answer:
a) The equation is:
Confidence Interval = Mean ± Z score × Standard deviation/√Number of samples
b) The 98% confidence interval = (5.62784, 6.37216)
Step-by-step explanation:
a. Write down the equation you should use to construct the confidence interval for the average number of days absent per term for all the children. (10 points)
Confidence Interval = Mean ± Z score × Standard deviation/√Number of samples
b. Determine a 98% confidence interval estimate for the average number of days absent per term for all the children. (10 points)
Confidence Interval = Mean ± Z score × Standard deviation/√Number of samples
Mean = 6 days
Standard deviation = 1.6 days
Number of samples = 100
Z score of 98% confidence interval = 2.326
Confidence interval = 6 ± 2.326 × 1.6/√100
= 6 ± 2.326 × 1.6/10
= 6 ± 0.37216
= 6 - 0.37216
= 5.62784
6 + 0.37216
= 6.37216
Therefore, the 98% confidence interval = (5.62784, 6.37216)
Answer:
The average speed of the first plane is 315 mph and that of the second plane is 105 mph.
Step-by-step explanation:
Let us assume that the first plane has speed x mph and that of the second plane is y mph.
So, as per given condition x = 3y ......... (1)
Now, given that after traveling in the same direction for 7.5 hours, they are 1575 miles apart.
So, we write the equation as
7.5x - 7.5y = 1575
⇒ x - y = 210 ........ (2)
Now, solving equation (1) and (2) we get, 3y - y = 210
⇒ 2y = 210
⇒ y = 105 mph
So, from equation (1) we get, x = 3y = 315 mph.
So, the average speed of the first plane is 315 mph and that of the second plane is 105 mph. (Answer)
Answer:
51
Step-by-step explanation:
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